Question

Write the standard form of the line that passes through the given points. include your work in your final answer. (-1, -3) and (2, 1)

Answer 1

The standard form of a line passing through the points (-1, -3) and (2, 1) is 4x - 3y = 5.

The slope of the given line, m = (1 - (-3))/(2 - (-1)) = (1 + 3)/(2 + 1) = 4/3.

Computed using the formula for the slope of a line, m = (y₂ - y₁)/(x₂ - x₁), when a line passes through the points (x₁, y₁) and (x₂, y₂).

The point intercept form of a line is y - y₁ = m(x - x₁) when the line passes through the point (x₁, y₁) and has the slope m.

Thus, the given line in the point intercept form can be written as:

y - 1 = (4/3)(x - 2).

The standard form of a line is ax + by = c.

To convert the point intercept form to the standard form, we do as follows:

y - 1 = (4/3)(x - 2),

or, 3(y - 1) = 3(4/3)(x - 2) {Multiplying both sides by 3},

or, 3y - 3 = 4x - 8 {Simplifying},

or, 8 - 3 = 4x - 3y {Rearranging},

or, 4x - 3y = 5 {Rearranging and simplifying}.

Thus, the standard form of a line passing through the points (-1, -3) and (2, 1) is 4x - 3y = 5.

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