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erastova [34]
2 years ago
14

PLEASE HELP!!!!!!!

Mathematics
1 answer:
posledela2 years ago
8 0

90° = complimentary

middle one = is neither

3rd one is supplementary

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- 4B - 2C when b equals 2.5 + C equals 3
ryzh [129]

-4b - 2c =

(-4 × 2.5) - (2 × 3)

-10 - 6

= -16



So, -4b - 2c = -16


Hope this helps and let me know if anymore help is needed!!

3 0
3 years ago
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One gallon of water weighs 8.34 pounds. How much does 6 gallons of water weigh? Label your answer.
Anettt [7]
If 1 gallon weighs 8.34 lbs.....then 6 gallons weighs (6 * 8.34) = 50.04 lbs
8 0
3 years ago
Read 2 more answers
A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of
yan [13]

Answer:

"The probability that the mean battery life would be greater than 948.8 minutes" is 0.1446.

Step-by-step explanation:

In this case, the quality control expert takes a <em>sample</em> of batteries. From these batteries, we want to find "the probability that the mean battery life would be greater than 948.8 minutes".

Different concepts needed to take into account to solve this question

Sampling Distribution of the Means

For doing this, we need to use the sampling distribution of the means, which results from taking the mean for each possible sample coming from a random variable \\ x. Roughly speaking, each sample will have a different mean, \\ \overline{x}, and the probability distribution for any of these means is called the <em>sampling distribution of the means</em>.

The sampling distribution of the means has a mean that equals the population's mean for the random variable \\ x, i.e., \\ \mu, and its standard deviation is \\ \frac{\sigma}{\sqrt{n}}. We can express this mathematically as:

\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [1]

Standardized Values for \\ \overline{x}

We can standardized the values for \\ \overline{x} using <em>z-scores</em>:

\\ Z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}} [2]

This random variable \\ Z follows a <em>standard normal distribution</em>, that is, \\ Z \sim N(0,1), and it is easier to find probabilities since the values for them are tabulated in the <em>standard normal table</em> (available in any Statistics book or on the Internet.)

What type of distribution follows the sampling distribution of the means?

A general rule of thumb is that this distribution (the sampling distribution of the means) follows a <em>normal distribution</em> if the sample size, \\ n, is bigger than or equal to 30 observations, or \\ n \geq 30. In this case, \\ n = 109 batteries. This is a result from the Central Limit Theorem, fundamental in Statistical Inference.

Standard Deviation

We have to remember that the standard deviation is the square root of the variance \\ \sigma^2, or \\ \sqrt{\sigma^2}.

  • \\ \sigma^{2} =5929
  • \\ \sigma = \sqrt{5929} = 77

Therefore, the standard deviation in this case is \\ \sigma = 77 minutes.

In sum, we have the following information to answer this question:

  • \\ \sigma = 77 minutes.
  • \\ \mu = 941 minutes.
  • \\ n = 109 batteries (the sample size is <em>large enough</em> to assume that the sampling distribution of the means follows a <em>normal distribution</em>).
  • \\ \overline{x} = 948.8 minutes.

What is the probability that the mean battery life would be greater than 948.8 minutes?

Well, having all the previous information, we can use [2] to solve this question (without using units):

\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ z = \frac{948.8 - 941}{\frac{77}{\sqrt{109}}}

\\ z = \frac{7.8}{\frac{77}{\sqrt{109}}}

\\ z = \frac{7.8}{7.37526}

\\ z = 1.05758 \approx 1.06

This result is the <em>standardized value</em> or <em>z-score</em> for \\ \overline{x}, considering \\ \mu = 941 and \\ \sigma = 77.

We round <em>z</em> to two decimals digits since <em>standard normal table</em> only uses it as an entry to find probabilities.

With \\ z = 1.06, we can consult the <em>cumulative standard normal table. </em>First, we need to find with \\ z = 1.0 in the first column in the table. Then, in its first raw, we need to find +0.06. The intersection for these two values determines the cumulative probability for \\ P(z.

It is important to recall that \\ P(z because \\ z = 1.06 is the standardized value for \\ \overline{x} = 948.8 minutes.

Then,  \\ P(z

However, the question is about \\ P(\overline{x} > 948.8) = P(z>1.06)

And

\\ P(\overline{x} > 948.8) + P(\overline{x} < 948.8) = 1

Or

\\ P(z>1.06) + P(z

Then

\\ P(z>1.06) = 1 - P(z

\\ P(z>1.06) = 1 - 0.8554

\\ P(z>1.06) = 0.1446

Therefore, "the probability that the mean battery life would be greater than 948.8 minutes" is 0.1446.

6 0
4 years ago
Straight white mail hate myself im so mad cause my skin so pale. <br> what this song
Gemiola [76]

Answer:

is it never gonna give you up by official rick astley

5 0
3 years ago
10.) Fishermen have been studying how the number of dead sea turtles in the local bay is related to the pollution index of the b
alexdok [17]

Answer:

Step-by-step explanation:

A linear function is a polynomial function of the first degree that has the form:

f (x) = m*x + b   or  y=m*x + b

where y is the dependent variable, x is the independent variable, m is the slope of the line and b is the intercept with the Y axis.

The slope m measures the inclination of the line with respect to the abscissa axis, that is, the x axis.  According to the value of the slope m, the linear function can be increasing if m> 0, decreasing if m <0 or constant if m = 0.

You know that the number of sea turtle deaths per year is modeled by f(x) = 13.42x + 109.118.   Then the value of the slope is 13.42. In this scenario, the slope indicates that the number of deaths of sea turtles grows in a proportion of 13.42 with respect to the pollution index of the bay.

5 0
4 years ago
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