Answer:
q = 224 mm, h ’= - 98 mm, real imagen
Explanation:
For this exercise let's use the constructor equation
where f is the focal length, p and q are the distance to the object and the image respectively.
In a mirror the focal length is
f = R / 2
indicate us radius of curvature is equal to the diameter of the eye
R = 3,50 10² mm
f = 3.50 10² /2 = 1.75 10² mm
they also say that the distance to the object is p = 0.800 10³ mm
1 / q = 1 / f - 1 / p
1 / q = 1 / 175 - 1 /800
1 / q = 0.004464
q = 224 mm
to calculate the size let's use the magnification ratio
m = 
h '= 
h ’= - 224 350 / 800
h ’= - 98 mm
in concave mirrors the image is real.
Point of correction, spring constant is 2.3×10−2 m not 2.3×10−2 m m
Answer:
28577 N/m
Explanation:
From Hooke's law, F=kx where F is force applied, k is spring constant and x is compression
F=mg=67*9.81
Approximately, 28577 N/m
\[S = \Delta Q / T\] where S - entropy, Q heat and T temperature \[S = 295/402 = 0.733 \]
SO IT'S B
Answer:
511.1 J
Explanation:
We are given that
Mass of wood block=m=3 kg
Vertical distance,h=23 m
Horizontal distance =x=30 m
Distance traveled in downward direction y=40 m
Initial velocity,u=0
Where 
By work energy theorem
Change in kinetic energy=Work done= mgh-W
Hence, the work done due to friction on the block as it slides down the ramp=511.1 J
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