The approximate amount of thrust(force) you need to apply to the lander to
keep its velocity roughly constant is zero.
<h3>What is Newton's second law of motion?</h3>
Newton's second law of motion states that the acceleration the force acting
on the object is directly proportional to its rate of change of momentum.
F = m a
If the object is moving with uniform velocity, it simply means that the
acceleration is zero, and the corresponding force will also be zero.
Read more about Constant velocity here brainly.com/question/3052539
Answer:
Induced current, I = 18.88 A
Explanation:
It is given that,
Number of turns, N = 78
Radius of the circular coil, r = 34 cm = 0.34 m
Magnetic field changes from 2.4 T to 0.4 T in 2 s.
Resistance of the coil, R = 1.5 ohms
We need to find the magnitude of the induced current in the coil. The induced emf is given by :

Where
is the rate of change of magnetic flux,
And 



Using Ohm's law, 
Induced current, 

I = 18.88 A
So, the magnitude of the induced current in the coil is 18.88 A. Hence, this is the required solution.
Answer:
The acceleration is 
Explanation:
Given the velocity function:

you can obtain the instantaneous acceleration "a" as its first derivative:

To determine the value of "a" when the velocity was 12m/s, you need to figure out the value for "t" when this happens. At what time t is the velocity 12m/s?

This value of t is less than the 5 seconds mentioned in the text - so that is a good sign that the formula is valid for this value. And so you can use t=3.47s in the derivative (acceleration) above:
Answer:
Explanation:
Using the formula : E = mc²
Where m = mass = 6.8 × 10^-6 kg
c = speed of light = 3 ×10^8 m/s
The amount of joules of energy that would be produced equals :
Plugging in our values :
E = mc²
E = (6.8 × 10^-6) kg × (3 ×10^8)²m/s
E = (6.8 × 10^-6) kg × 9 × 10^16 m/s
E = 61.2 × 10^(-6 + 16)
E = 61.2 × 10^10 J