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Dvinal [7]
2 years ago
12

Một vật chuyển động từ A đến B cách nhau 90m . Trong nữa đoạn đường đầu vật đi với vận tốc v2 =5m/s , giữa đoạn đường còn lại vậ

t chuyển động với vận tốc v2=3m/s. Sau bao lâu vật đến B
Physics
1 answer:
Rainbow [258]2 years ago
6 0

お前なに言ってんのか全然わかんない...

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Forces that are equal in size but opposite in direction are ____.
Alchen [17]

Answer: The correct answer is balanced force.

Explanation:

Balanced forces are balanced when the forces are acting equal in magnitude but opposite in direction. The balanced forces will not cause change in the speed of the object.

Unbalanced forces are unbalanced when the forces acting on the object are not equal in magnitude. The combined force is the difference between the forces. It will cause the change in the speed of the body.

Therefore, forces that are equal in size but opposite in direction are balanced.

8 0
3 years ago
What is the length of the blues progression in this excerpt?
Gre4nikov [31]
<span>In blues musicians also often refer to chord progressions using Roman numerals, as this facilitates transposing a song to a new key. For example, rock and blues musicians often think of the 12 bar blues as consisting of I, IV and V chords. Thus a simple version of the 12 bar blues might be expressed as I/I/I/I IV/IV/I/I V/IV/I/I. By thinking of this blues progression in Roman numerals, a backup band or rhythm section could be instructed by a band leader to do the chord progression in any key. For example if the band leader asked the band to play this chord progression in the key of C Major, the chords would be C/C/C/C F/F/C/C G/F/C/C.</span>
5 0
3 years ago
PLEASE HELP IF U PASS TESTS
bezimeni [28]
I think iron? i’m not 100% sure
5 0
3 years ago
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What is a disadvantage of the inefficiency of cars?
Stella [2.4K]
The answer is air pollution
6 0
3 years ago
The record distance in the sport of throwing cowpats is 81.1 m. This record toss was set by Steve Urner of the United States in
N76 [4]

Answer:

28.2 m/s

Explanation:

The range of a projectile launched from the ground is given by:

d=\frac{v^2}{g}sin 2\theta

where

v is the initial speed

g = 9.8 m/s^2 is the acceleration of gravity

\theta is the angle at which the projectile is thrown

In this problem we have

d = 81.1 m is the range

\theta=45^{\circ} is the angle

Solving for v, we find the speed of the projectile:

v=\sqrt{\frac{dg}{sin 2 \theta}}=\sqrt{\frac{(81.1 m)(9.8 m/s^2)}{sin (2\cdot 45^{\circ})}}=28.2 m/s

7 0
3 years ago
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