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2 years ago

IM IN A HURRY PLEASE HELP ME QUESTION IS DOWN BELOW WORTH 15 POINTS each

Mathematics

1 answer:

Blizzard [7]2 years ago

5 0

The value of x is 2 and the length of JK is 4

<h3>How to solve the unknown variables?</h3>

The given parameters from the circle are:

Center = Point S
Segment JK = 8
Segment LK = 2x + 4
Congruent SN = SP = 7

The lines SR and SQ are the radii of the circle P

This means that lines JK and JL are congruent

So, we have:

JK = KL

Substitute LK = 2x + 4 and JK = 4

4 = 2x + 4

Rewrite the above equation as:

2x + 4 = 8

Subtract 4 from both sides

2x + 4 - 4 = 8 - 4

Evaluate the difference

2x = 4

Divide both sides by 2

2x = 4/2

This gives

x = 2

Substitute x = 2 in LK = 2x + 4

LK = 2*2 + 4

Evaluate the product of 2 and 2

LK = 4 + 4

This gives

LK = 8

The point N divides JK into 2 equal segments

So, we have

JN = JK/2

JN= 8/2

JN = 4

Hence, the value of x is 2 and the length of JK is 4

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PLEASE HELP!!!<br> A)<br> B)<br> C)<br> D)

Vlad1618 [11]

Answer:

b i think

Step-by-step explanation:

4 0

3 years ago

How many solutions are there to the equation below? 4(x-5)=4x-24

blondinia [14]

It is a linear equation so there can be 1 solution, 0 solutions, or infinite solutions

4(x-5)=4x-24

distribute

4x -20 = 4x-24

subtract 4x from each side

-20 = -24

no solutions

6 0

3 years ago

Read 2 more answers

50 men working 10 hours daily can complete a job in

Sliva [168]

<h2>Given :-</h2>

50 men do 10 hours work daily complete work in 20 days

80 men do job in 50% time

Days required

<h2>Solution :-</h2>

1 man may do job in (50 × 20) days =
1 man may do job in 1000 days

Now,

80 man = 1000/80 = 12.5

Now,

When hours reduced 50% then we will multiply days by 2
Total days = 12.5 × 2 = 25 days.

<h2>Hence</h2>

Option C is correct

$\begin{gathered} \\ \end{gathered}$

8 0

3 years ago

Solve each equation by completing the square : <br> NEED THIS IN 10 MINS WILL GUVE BRAINLIEST

ololo11 [35]

Can barely see the questions ! Retake a picture if you can.

8 0

3 years ago

how much would $150 invested at 8% interest compounded anually be worth after 13 years? A(t)=P(1+r/n)^

PIT_PIT [208]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$150\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &13
\end{cases}
\\\\\\
A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589$

3 0

3 years ago