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Lady_Fox [76]
2 years ago
12

IM IN A HURRY PLEASE HELP ME QUESTION IS DOWN BELOW WORTH 15 POINTS each

Mathematics
1 answer:
Blizzard [7]2 years ago
5 0

The value of x is 2 and the length of JK is 4

<h3>How to solve the unknown variables?</h3>

The given parameters from the circle are:

  • Center = Point S
  • Segment JK = 8
  • Segment LK = 2x + 4
  • Congruent SN = SP = 7

The lines SR and SQ are the radii of the circle P

This means that lines JK and JL are congruent

So, we have:

JK = KL

Substitute LK = 2x + 4 and JK = 4

4 = 2x + 4

Rewrite the above equation as:

2x + 4 = 8

Subtract 4 from both sides

2x + 4 - 4 = 8 - 4

Evaluate the difference

2x = 4

Divide both sides by 2

2x = 4/2

This gives

x = 2

Substitute x = 2 in LK = 2x + 4

LK = 2*2 + 4

Evaluate the product of 2 and 2

LK = 4 + 4

This gives

LK = 8

The point N divides JK into 2 equal segments

So, we have

JN = JK/2

JN= 8/2

JN = 4

Hence, the value of x is 2 and the length of JK is 4

Read more about circles at:

brainly.com/question/11833983

#SPJ1

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Help plz will mark brainliest.
vodomira [7]
Tan M = opposite / adjacent
tan M = KL / KM
tan M = 15/8


Letter C
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Which of the points A(5, −3),B(−2, 4), C(0, 0),D(2, 1), E(−5, 2.5) belong to the graph of y= 1 2 x?
ohaa [14]

Answer:

the slope makes no sense

Step-by-step explanation:

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Which statement is true?
meriva

Answer:

The correct answer is A I believe . . .

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2 years ago
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What is the scientific notation of 0.000000045?
morpeh [17]
The answer is 4.5 × 10 -8
4 0
3 years ago
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Find the equation of the line that passes through points (3,5) and (-6,2). Write the equation in slope intercept form.
andrezito [222]
1)  gradient of line = Δ y ÷ Δ x
                              = (5 -2) ÷ (3 - (-6))
                              = ¹/₃
   
     using the point-slope form (y-y₁) = m(x-x₁)
     using (3,5)
           (y - 5) = ¹/₃ (x -3)
             y - 5  = ¹/₃x - 1
        ⇒      <span>  y =   ¹/₃ x  + 4  [OPTION D]


</span>2)        y =  2x  +  5  .... (1)
<span>           </span>y = ¹/₂ x  + 6  .... (2)
       
         by substituting y in (1) for y in (2)

           2x  +  5 = ¹/₂ x  + 6 
                 ³/₂ x = 1
                      x = ²/₃

        by substituting found x (2)

            y = ¹/₂ (²/₃)  + 6
            y = ¹⁹/₃

∴ common point is (²/₃ , ¹⁹/₃)  thus answer is FALSE [OPTION B]


3) Yes [OPTION A]
     This is because the both have a gradient of 5 and if they have the same gradient then that means that the two lines are parallel to each other.

4) No [OPTION B]
       Two lines are perpendicular if their gradients multiply to give - 1 and as such one is the negative reciprocal of the other.  Since both gradients are ¹/₂ then they are actually parallel and not perpendicular.

6 0
3 years ago
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