Three fair, standard six-faced dice of different colors are rolled. In how many ways can

Mathematics

2 answers:

kap26 [50]2 years ago

6 0

These are some of the ways you can make 15 by adding three numbers together.

The first way is doing 6+6+3.There are some more ways to do it too.

2nd way is 6+4+5.

3. 1+6+6

4. 5+5+5

Sonbull [250]2 years ago

3 0

The answer to this question is 8

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What is the solution to | 2x-4| >8?

Serga [27]

$| 2x-4| \ \textgreater \ 8 \\ \\ 2x - 4 \ \textgreater \ 8 \ , \ -(2x - 4) \ \textgreater \ 8 \ / \ break \ problem \ into \ 2 \ equations \\ \\ first \ equation \\ \\ 2x \ \textgreater \ 8 + 4 \ / \ add \ 4 \ to \ each \ side \\ \\ 2x \ \textgreater \ 12 \ / \ simplify \\ \\ x \ \textgreater \ \frac{12}{2} \ / \ divide\ each \ side \ by \ 2 \\ \\ x \ \textgreater \ 6 \ / \ simplify \\ \\ second \ equation \\ \\ -2x + 4 \ \textgreater \ 8 \ / \ simplify \\ \\ -2x \ \textgreater \ 8 - 4 \ / \ subtract \ 4 \ from \ each \ side \\ \\ -2x \ \textgreater \ 4 \ / \ simplify \\ \\ x \ \textless \ \frac{4}{-2} \ / \ divide \ each \ side \ by \ -2 \\ \\$
$\\ \\ x \ \textless \ - \frac{4}{2} \ / \ simplify \\ \\ x \ \textless \ - 2 \ / \ simplify \\ \\ collect \ solutions \\ \\ x \ \textgreater \ 6 \ , \ x \ \textless \ -2 \\ \\$

So, your answer to this problem is x > 6 and x < -2.

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3 years ago

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Thepotemich [5.8K]

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3 years ago

Jacki evaluated the expression below.

Maru [420]

Answer: Jacki did not subtract 12 from 8 correctly

Step-by-step explanation: it should be -4