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1 year ago

Which term is not possible in the domain of a sequence?

Mathematics

1 answer:

ycow [4]1 year ago

8 0

The term that is not possible in the domain of a sequence is:

-5

<h3>What is the domain of a function?</h3>

The domain of a function is the set that contains all possible input values for the function. For a sequence, the domain is the set that contains all the indexed of the terms, starting at 0 and going until the nth term.

For example, suppose we have the following sequence: 3, 5, 7, ...

The term with index 0 is 3.

The term with index 1 is 5.

The term with index 2 is 7.

From what was explained above, which also can be visualized with the example, an index term of a sequence cannot be negative, hence the term that is not possible in the domain of a sequence is:

-5.

Which is the only negative number of the options.

More can be learned about the domain of a function at brainly.com/question/10891721

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What is the simplified form of 4x plus 2 over x plus 5 minus the fraction 3x plus 1 over x plus 5?

viva [34]

We have that

[(4x+2)/(x+5)]-[(3x+1)/(x+5)]
<span>They have common denominators, so just add the numerators like normal fractions:</span>
=[(4x+2)-(3x+1)]/(x+5)
=[(4x+2-3x-1)]/(x+5)
=[(x+1)]/(x+5)

the answer is
(x+1)/(x+5)

4 0

3 years ago

Read 2 more answers

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

7 0

3 years ago

How do you graph the line on a graph

kotykmax [81]

by starting from the number on the z axis and going up from the y axis

5 0

3 years ago

Find the equation of the line passing through the points (3,7) and (-2,5)

r-ruslan [8.4K]

Answer:

The equation of the line passing through the points (3,7) and (-2,5) is y=⅖x+29/5

Step-by-step explanation:

Greetings !

$first \: find \: the \: slope \: m \\ m = \frac{(Y₂-Y₁)}{(X₂-X₁)} ..substitute \: vlues \\ m = \frac{(5 - 7)}{( - 2 - 3)} = \frac{ - 2}{ - 5} = \frac{2}{5} \\ y = mx + b \: to \: find \: equation \: of \: aline \\ between \: two \: poins and \: use \: \\ one \: of \: the \: two \: points \: lets \: take( - 2.5) \\ y = mx + b \\ 5 = \frac{ - 2}{5} ( - 2) + b \\ 5 = \frac{ - 4}{5} + b \\ 5 + { - 4}^{5} = b \\ \frac{25 + 4}{5} = b \\ b = \frac{29}{5} \\ finally \: equation \: of \: the \: line \: will \: be \\ y = \frac{2}{5} x + \frac{29}{5}$

7 0

2 years ago

What is the measure of

Ede4ka [16]

Hey there! :)

Answer:

m∠A = 72°.

m<B = 108°.

Step-by-step explanation:

In a parallelogram, the opposite angles are congruent.

Therefore, we can set the two expressions equal to each other:

5y - 3 = 3y + 27

Add 3 to both sides:

5y = 3y + 30

Subtract 3y from both sides:

2y = 30

Divide both sides by 2:

y = 15

Substitute this value of y into an expression to solve for the measure of ∠A:

5(15) - 3 = 72°. m∠A = 72°.

In parallelograms, the neighboring angles are supplementary. Therefore:

m∠A + m∠B = 180°

72° + m∠B = 180°

m<B = 108°.

5 0

3 years ago