Can anyone help me solve these linear systems using substitution?
1 answer:
The system of the linear systems of equation using substitution is;
- x = 2, y = 2
- x = -20, y = -1
<h3>Linear equation</h3>
3x-y=4
x+2y=6
from (2)
x = 6 - 2y
substitute into (1)
3x-y=4
3(6 - 2y) - y = 4
18 - 6y - y = 4
- 6y - y = 4 - 18
-7y = -14
y = 2
Substitute into
x+2y=6
x + 2(2) = 6
x + 4 = 6
x = 6 - 4
x = 2
2. 2x-y= -39
x+y= -21
From (2)
x = -21 - y
substitute into
2x-y= -39
2(-21 - y) - y = -39
-42 - 2y - y = -39
- 2y - y = -39 + 42
- 3y = 3
y = 3/-3
y = -1
substitute into
x+y= -21
x + (-1) = -21
x - 1 = -21
x = -21 + 1
x = -20
3. 2x+y =11
6x-5y =9
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16/3 because you put a 1 under 8 since it's not a fraction hen multiple across
Step-by-step explanation:
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If number of nickel = n
number of dimes = 3n
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In short, Your Answer would be Option C
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