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Phoenix [80]
2 years ago
10

Can anyone help me solve these linear systems using substitution?

Mathematics
1 answer:
vivado [14]2 years ago
6 0

The system of the linear systems of equation using substitution is;

  • x = 2, y = 2
  • x = -20, y = -1

<h3>Linear equation</h3>

3x-y=4

x+2y=6

from (2)

x = 6 - 2y

substitute into (1)

3x-y=4

3(6 - 2y) - y = 4

18 - 6y - y = 4

- 6y - y = 4 - 18

-7y = -14

y = 2

Substitute into

x+2y=6

x + 2(2) = 6

x + 4 = 6

x = 6 - 4

x = 2

2. 2x-y= -39

x+y= -21

From (2)

x = -21 - y

substitute into

2x-y= -39

2(-21 - y) - y = -39

-42 - 2y - y = -39

- 2y - y = -39 + 42

- 3y = 3

y = 3/-3

y = -1

substitute into

x+y= -21

x + (-1) = -21

x - 1 = -21

x = -21 + 1

x = -20

3. 2x+y =11

6x-5y =9

Learn more about linear equation:

brainly.com/question/4074386

#SPJ1

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The system of equations that could be graphed to solve the equation given is

  • y = \log_{0.5}(x)\\\\
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<h3>How can we form a system of equations from an equation?</h3>

Suppose the equation be a = b\\

Let there is a symbol c such that we have a = b = c

It is because a and b are same measure (that is exactly what a = b means)

and we gave another name c to that measure.

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<h3>Using the above method to find the system of equations needed</h3>

Since the given equation is log_{0.5}(x) = log_2(2+x)

The 2d graphs are usually expressed as y = f(x) on X-Y plane.

Taking the equation's expressions equal to y, we get

log_{0.5}(x) = log_2(2+x) = y

or, we get system of equations as

y = log_{0.5}(x)\\\\y = log_3{(2 + x)}

Their graph is plotted below. The intersection point of both curves is the solution to the given equation as it satisfies both the equations of the system of equations formed from the given equation.

Thus,

The system of equations that could be graphed to solve the equation given is

  • y = \log_{0.5}(x)\\\\
  • y = \log_3(2+x)

Learn more about solutions to system of equations here:

brainly.com/question/14550337

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