Answer:
Principal = Total ÷ (1 + Rate)^years
That formula is found here: http://www.1728.org/compint2.htm
Principal = 3.000 / (1.03) ^ 15
Principal = 3.000 / 1.5579674166
Principal = $1,925.59
Step-by-step explanation:
Y is 7.5
A easy way to do it is simply graph it or divide it!
For instance, since x=5 is half of x=10, we would just divide 15 by 2 to get Y which is 7.5
Answer: 
Step-by-step explanation:
<h3>
The complete exercise is: "A rectangular yard is 20 ft by 15 ft. The yard is cover with grass except for 8.5 feet square flower garden. How much grass is in the yard?"</h3><h3 />
The area of a rectangle can be calculated with the following formula:

Where "l" is the lenght of the rectangle and "w" is the width.
Based on the data given in the exercise, you can identify tha the length and the width of the rectangular yard are:

Then, you can substitute these values into the formula and then evaluate in order to find the area of the entire yard:

The area of the flower garden which is an square, can be calculated with this formula:

Where "s" is the side length.
In this case you know that:

Then the area of the flower garden is:

<em> </em>Since this is not covered with grass, you need to subtract both areas calculated above in order to find the surface covered with grass in the yard.
This is:

Answer:
The expected amount for a duration of 20 weeks is $9.4
<em></em>
Step-by-step explanation:
Read attachment to understand the complete question
From the question, we have the following given parameters:
x = Amount paid for a second movie
--- Expected value of x
--- Standard deviation of x
Required
Determine the total amount paid for a second movie for 20 weeks
The required implies that we calculate the expected value for a duration of 20 weeks.
i.e.
If

Then:

Substitute 20 for n

Substitute 0.47 for E(x)


<em>Hence, the expected amount for a duration of 20 weeks is $9.4</em>
Answer:
1 the first one
Step-by-step explanation: its biased as you are asking people wearing football jerseys, hinting that they like football.