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PIT_PIT [208]
2 years ago
5

Find cos B, sinB,tanb

Mathematics
1 answer:
emmasim [6.3K]2 years ago
6 0

Using right triangle relations, we will get:

  • tan(B) = 1.05
  • sin(B) = 0.735
  • cos(B) =  0.7

<h3>How to find the value of the trigonometric equations?</h3>

We assume that bot triangles are equivalent, then the angle B will be the same as the angle Z.

Now remember the relations:

  • tan(θ) = (opposite cathetus)/(adjacent cathetus).
  • sin(θ) = (opposite cathetus)/(hypotenuse)
  • cos(θ) = (adjacent cathetus)/(hypotenuse).

If we step on angle B, we have:

  • opposite cathetus = 29.4
  • adjacent cathetus = 28
  • hypotenuse = 40.6

Replacing that, we get:

  • tan(B) = 29.4/28 = 1.05
  • sin(B) = 29.4/40.6 = 0.735
  • cos(B) = 28/40.6 = 0.7

If you want to learn more about trigonometric functions:

brainly.com/question/8120556

#SPJ1

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If m&lt;2=35° and &lt;1and &lt;2 form a right angle. Find m &lt;1.
yaroslaw [1]
To solve this problem, we just need to set up a simple equation. We have that angles 1 and 2 add up to equal a right angle, or 90°, and that m<2 is 35°, so we just have to do a bit of subtraction.

<1 + <2 = 90   Given
<1 + 35 = 90   Substitute 35 for <2
<1 = 55°   Subtract 35 from both sides to get rid of it, since subtraction is the opposite of addition.

Therefore, m<1 = 55°.

Hope this helps!
4 0
4 years ago
Thank you so much im confused ​
svp [43]

Answer:

The period of this graph is 10

Step-by-step explanation:

The period is defined as the length of one wave of the function, in this case, the graph

3 0
2 years ago
in a class, 60% of the students are girls. there are 19 girls in the class. how many students are there? how many boys are there
Slav-nsk [51]
60/40 =19/? 19 ×40÷60=13 there is 13 boys
4 0
3 years ago
How do i solve this?
dangina [55]

\text{Given that, f(x) = 2x+5}\\\\f(-1) = 2(-1)+5 = -2+5= 3\\\\f(2)  = 2(2)+5 =  4+5 = 9\\\\f(0)  =2(0)+5 = 0+5=5\\\\f(z) = 2z+5

8 0
2 years ago
Solve the inequality |6x + 2| &lt; 10 and graph its solution.
mars1129 [50]
This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3

Second part: when (6x + 2) is negative.

-(6x + 2) < 10   Divide both sides of inequality by -1 and change the sign.

  (6x + 2) > -10
   6x + 2 > -10
   6x > -10 - 2
   6x > -12        Divide both sides by 6.
     x > -12/6
     x > -2.

Combined solution:   x < 4/3  and x > -2

  -2 < x < 4/3.

Graph is a line on the number line between -2 and 4/3.  
 
-2 and 4/3 are excluded from solution.
8 0
3 years ago
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