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iragen [17]
2 years ago
15

Find the mean for the amounts: $17,484, $14,978, $13,521, $14,500, $18,540, $14,978

Mathematics
1 answer:
DIA [1.3K]2 years ago
7 0

Answer:

$15666.83 (2dp)

Step-by-step explanation:

Mean = Total of all values / Number of Values

= \frac{17484+14978+13521+14500+18540+14978}{6}

=\frac{94001}{6}

= $15666.83 (2dp)

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denpristay [2]

Answer:

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8 0
3 years ago
12. Show how to use the Distributive<br> Property to divide 54 by 2 by breaking<br> 54 into 40 + 14.
SOVA2 [1]

Answer:

40/2+14/7=27

Step-by-step explanation:

First I would break it down int 50 + 4 but either way you divide both by two

8 0
4 years ago
Mr. Jones is getting a 6% raise. If he made $720 a week, how much more will he make with the raise?
kirill115 [55]

$720 * .06 = 43.2

He will make $43.20 more each week.

7 0
3 years ago
You are saving for a skateboard that costs $125. Your aunt gives you $45 to start and you save $3 each week. The expression 45 +
AnnZ [28]

Answer:

4 weeks= $57

45+3(4)

45+12=57

10 weeks= $75

45+3(10)

45+30=75

15 weeks= $90

45+3(15)

45+45=90

20 weeks=$105

No there is not enough money because you are $20 short after 20 weeks. You need to wait 7 more weeks




5 0
3 years ago
Quadrilateral ABCD undergoes a reflection across the x-axis to form quadrilateral A'B'C'D'. The coordinates of A' are ( , ).
natka813 [3]
1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)

When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate  just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)

2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;

A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
5 0
3 years ago
Read 2 more answers
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