Ask question

Ask question

All categories

3 years ago

12

What is 10 feet to yards?

1 answer:

irinina [24]3 years ago

7 0

Answer:

is would be 3 yards and a foot

You might be interested in

Make a box and whisker plot of the data.<br><br> 24, 18, 29, 21, 16, 23, 13, 11

Elanso [62]

To make a box and whisker plot you must first order the data:

11, 13, 16, 18, 21, 23, 24, 29

Then find the median:

19.5

Then split the data into two sections by the median:

11, 13, 16, 18 and 21, 23, 24, 29

Now find the medians of those sets

14.5 and 23.5

With this information we can conclude Option C is the correct plot

Hope this helps!

7 0

3 years ago

Read 2 more answers

Divide 15 by v. Then, subtract 7.

rosijanka [135]

A is the correct answer

hope that helps:)

4 0

3 years ago

Read 2 more answers

PLS HELP WILL MARK BRAINLIEST!

elena-s [515]

More than means addition.

C is the correct option.

= (2x + 4) + 9 - 4y + 3x

= 2x + 4 + 9 - 4y + 3x

= 5x + 13 - 4y

= 5x - 4y + 13

7 0

2 years ago

Read 2 more answers

Help me please i cant seem to get it

givi [52]

The diagnonals of a parallelogram bisect each other ,

so

=》 BD = 3x × 2

=》BD = 6x

and there's given that

=》

$BD = \dfrac{3}{5} AC$

=》

$6x = \dfrac{3}{5} \times 40$

=》

$x = \dfrac{24}{6}$

=》

$x = 4$

so, if x = 4 , then the given quadrilateral is a parallelogram.

7 0

2 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

4 0

2 years ago