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Vedmedyk [2.9K]
2 years ago
14

What are the solutions of the system of equations y = –(x + 2)2 + 1 and y = 2x + 5?

Mathematics
1 answer:
Scilla [17]2 years ago
8 0

Answer:

(–4, 5) and (–2, 1)

Step-by-step explanation:

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Step-by-step explanation:

In the figure attached you can see two right triangles  triangle ABD and a triangle ACD.

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Keep on mind that:

tan\alpha=\frac{opposite}{adjacent}

Therefore:

<em>For the triangle ABD</em>:

tan(36\°)=\frac{x}{DC+11}    [EQUATION 1]

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tan(46\°)=\frac{x}{DC}    [EQUATION 2]

Solve from DC from [EQUATION 2]:

DC=\frac{x}{tan(46\°)}

Substitute into [EQUATION 1] and solve for x:

tan(36\°)=\frac{x}{(\frac{x}{tan(46\°)}+11)}\\tan(36\°)(\frac{x}{tan(46\°)}+11)=x\\11*tan(36\°)=x-\frac{xtan(36\°)}{tan(46\°)}\\7.991=0.298x

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3 years ago
Verify and show work<br><br> csc x - cos x • cot x = sin x
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∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M

∴ (sin²x + 1 - sin²x)/sinx = √3

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Answer:

None

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