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Firdavs [7]
3 years ago
12

Identify the dependent and independent variables in each situation.

Mathematics
2 answers:
klemol [59]3 years ago
6 0
A. independent (x) - expenses, dependent (y) - total cost
B. independent (x) - area, dependent (y) - price
C. independent (x) - time, dependent (y) - distance
D. independent (x) - size of carton, dependent (y) - number of items
    
lubasha [3.4K]3 years ago
3 0

Answer:

A. Dependent Variable: Total Cost of running a business and Independent Variable: Expenses.

B. Dependent Variable: Price of house and Independent Variable: Area.

C. Dependent Variable:  Time to run a certain distance and Independent Variable: Distance.

D. Dependent Variable:  Number of items in a carton and Independent Variable: Size of the carton.

<em>Further, The variable that we can change is called the Independent variable.</em>

<em>  The dependent variable depends upon the independent variable, as we change the value of the independent variable the value of the dependent variable is also get changed.</em>

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What is the slope of a line with points (-2, 1) and (0, 2)?
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Answer:

slope: 0.75

Step-by-step explanation:

y = 0.5x + 2

or

y =  

1/2x+2

When x=0, y = 2

When y=0, x = -4

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3 years ago
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An orchard produced 526.96 liters of fresh-squeezed orange juice over the course of 6 days. To the nearest thousandth of a liter
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Answer:

Hello!!

If an orchard produced 526.96 liters of fresh-squeezed orange juice over the course of 6 days. To the nearest thousandth of a liter, there was 87.827 liters of juice produced each day on average.

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7 0
3 years ago
A. Use the​ one-mean t-interval procedure with the sample​ mean, sample​ size, sample standard​ deviation, and confidence level
PtichkaEL [24]

Answer:

a) (17.227, 22.773)

b) 2.773

c) 2.773

Step-by-step explanation:

Given:

Sample size, n = 25

Standard deviation, s = 4

Sample mean, x' = 20

Level of significance, a = 0.98 = 1 - 0.98 = 0.02

The degrees of freedom, df, for a t-distribution = n - 1 = 25 - 1 = 24

Using the t table, the Critical value = t_\alpha _/_2, _d_f = t_0_._0_2_/_2, _2_4 = t_0_._0_1_, _2_4 = 3.4668

Margin of error, E = t_\alpha _/_2, _d_f * \frac{\sigma}{\sqrt{n}} = 3.4668 * \frac{4}{\sqrt{25}} = 2.773

Limits of 98% confidence interval, we have:

Lower limit : x' - M.E = 20 - 2.773 = 17.227

Upper limit: x' + M.E = 20 + 2.773 = 22.773

Therefore, (17.227, 22.773) is 98% confidence interval.

b) Let's the margin of error by taking half the length of the confidence interval.

Since we are to use half the length of CI, we have:

M.E = \frac{22.773 - 17.227}{2} = 2.773

c)M.E = t_\alpha _/_2, _d_f *s/\sqrt{n}

= t * \frac{s}{\sqrt{n}} = 3.4668 * \frac{4}{\sqrt{25}} = 2.773

4 0
3 years ago
How is finding the factors of a number different from finding the prime factorization of a number?
Hunter-Best [27]
Finding the factors of a number involves both prime and composite numbers while finding the prime factors of a number involves only prime numbers.
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