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3 years ago

Identify the dependent and independent variables in each situation.

2 answers:

6 0

A. independent (x) - expenses, dependent (y) - total cost
B. independent (x) - area, dependent (y) - price
C. independent (x) - time, dependent (y) - distance
D. independent (x) - size of carton, dependent (y) - number of items

lubasha [3.4K]3 years ago

3 0

Answer:

A. Dependent Variable: Total Cost of running a business and Independent Variable: Expenses.

B. Dependent Variable: Price of house and Independent Variable: Area.

C. Dependent Variable: Time to run a certain distance and Independent Variable: Distance.

D. Dependent Variable: Number of items in a carton and Independent Variable: Size of the carton.

Further, The variable that we can change is called the Independent variable.

The dependent variable depends upon the independent variable, as we change the value of the independent variable the value of the dependent variable is also get changed.

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Rita paid $82 for 5 trees and 1 shrub. Lilly bought 2 trees and 1 shrub for $37. Find the cost per tree and the cost per shrub.

N76 [4]

Answer:

trees cost $15

Shrub cost $7

Step-by-step explanation:

Given data

Rita paid $82 for 5 trees and 1 shrub

5x+y= 82---------1

Lilly bought 2 trees and 1 shrub for $37

2x+y= 37----------2

from 1

y= 82-5x

put the value of y in 2

2x+82-5x= 37

2x-5x= 37-82

-3x=-45

x= 45/3

x=$15

put the value of x in 1

5(x)+y= 82

5*15+y=82

75+y=82

y=82-75

y=$7

Hence, trees cost $15

Shrub cost $7

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3 years ago

Figure GHTA below is a parallelogram. = 6 cm, = 8 cm, and the measure of = 60°. Find the area.

Kruka [31]

Answer:

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Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A bag contains tickets numbered 1 through 5. Use the probability distribution to determine the probability of drawing an odd num

Makovka662 [10]

Answer:

The probability of drawing an odd numbered ticket is 60%.

Step-by-step explanation:

Odd numbered tickets:

Probability of one is 1/5 plus half of 1/5.

$P(X = 1) = \frac{1}{5} + \frac{1}{10} = \frac{3}{10}$

Probability of 3 is half of 1/5.

$P(X = 3) = \frac{1}{10}$

Probability of 5 is 1/5. So

$P(X = 5) = \frac{1}{5}$

Probability of drawing an odd numbered ticket:

$p = P(X = 1) + P(X = 3) + P(X = 5) = \frac{3}{10} + \frac{1}{10} + \frac{1}{5} = \frac{4}{10} + \frac{2}{10} = \frac{6}{10} = 0.6$

0.6*100% = 60%

The probability of drawing an odd numbered ticket is 60%.

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3 years ago

How can the Associative, Commutative, and Distributive Properties be applied when performing operations on complex numbers and p

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By using Associative, Commutative, and Distributive Properties in performing operations on complex numbers and polynomials, you would be able to simplify correctly and simply. To combine complex numbers, you must distribute any coefficients in front of the parentheses. Then identify andcombine like terms by combining the real number parts and the imaginary number parts separately.

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3 years ago

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Soloha48 [4]

Answer:

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Step-by-step explanation:

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2 years ago