The percentage of population has a resting heart rate is 15.7%.
Given that the mean of the data is 70 beats per minute and standard deviation is 4 beats per minute.
A probability distribution is a mathematical function that describes the probability of several possible values of a variable.
Mean, μ=70
Standard deviation, σ=4
Given that the heart rate is resting between 74 and 82.
Now, we will use the standard normal formula
P(x₁<x<x₂)=P((x₁-μ)/σ<x<(x₂-μ)/σ)
Here x₁=74 and x₂=82.
Substitute these values in the formula, we get
P(74<x<82)=P((74-70)/4<x<(82-70)/4)
P(74<x<82)=P(4/4<x<12/4)
P(74<x<82)=P(1<x<3)
P(74<x<82)=P(x<3)-P(x<1)
Now, we will find the values by using the z-table, we get
P(74<x<82)=0.998-0.841
P(74<x<82)=0.157
P(74<x<82)=15.7%
Hence, the percentage of the population has a resting rate between 74 and 82 with the mean data is 70 beats per minute and the standard deviation data is 4 beats per minute is 15.7%.
Learn more about standard normal from here brainly.com/question/1407349
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