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Olin [163]
3 years ago
13

the depth of the ocean and a buoy reaches a maximum of 6 feet and a minimum of 2 feet. the depth d (in feet) of the ocean is mod

eled by h=2 sin pi/6t + 4 where t is the time (in hours) with t=0 representing 12 a.m.

Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0
C.) 5 = 2 sin pi/6 t + 4
2 sin pi/6 t = 5 - 4 = 1
sin pi/6 t = 1/2
pi/6 t = arcsin (1/2) = 2n pi + pi/6, (2n + 1)pi - pi/6 = pi/6(12n + 1), pi/6(12n + 5)
t = 12n + 1, 12n + 5, n = 0, 1, 2, . . . 
t = 1, 5

Therefore, the depth is 5 at 1 a.m. and at 5 a.m.
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A linear model of this situation contains the values (15, 300.2) and (26, 177.88) where x represents the number of square inches
maw [93]

Answer: Paula starts with 301.5 yarns.

Step-by-step explanation:

Equation of a line passing through two points (a,b) and (c,d) is given by:-

(y-b)=\dfrac{b-d}{a-c}(x-a)

Given: x=  number of square inches knitted on the scarf

y= number of yarns remaining on the ball of yarn

The equation of a line passing through (15, 300.2) and (26, 177.88):

(y-300.2)=\dfrac{26-15}{177.88-300.2}(x-15)\\\\\Rightarrow (y-300.2)=\dfrac{11}{-122.32}(x-15)\\\\\Rightarrow (y-300.2)=\dfrac{11}{-122.32}(x-15)

To find initial point, put x=0

y-300.2=-\dfrac{11}{122.32}(0-15)\\\\\Rightarrow\ y-300.2=\dfrac{375}{278}\\\\\Rightarrow\ y=\dfrac{375}{278}+300.2\\\\\Rightatrrow\ y=301.5  \ \ (approx)

Hence, Paula starts with 301.5 yarns.

5 0
3 years ago
A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs
Darina [25.2K]

Answer:

Total cost for tiles and paints is $924.  

Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)

\text{Area of walls and ceiling}=1200+90+120

\text{Area of walls and ceiling}=1410

Therefore, the area of walls and ceiling is 1410 square meters.

Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,  

\text{ The total painting cost}=10*(\frac{1410}{25})

\text{ The total painting cost}=10*56.4=564

Therefore, the total painting cost is $564.  

Tiles will be required for floor. Let us find the area of floor.

\text{Area of floor} = 40*3\text{ square meters}

\text{Area of floor} =120\text{ square meters}

Given: 1m squared floor tiles costs $3. So,  

\text{Total cost for tiles} = 3*120 = 360

Therefore, the total tiles cost is $360.

Now let us find combined total cost of tiles and paint.

\text{Combined total cost}= 564+360 = 924

Therefore, the combined total cost of tiles and paint is $924.

6 0
3 years ago
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nika2105 [10]

Answer:

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Step-by-step explanation:

3 0
3 years ago
How do you find the perimeter of a square?
riadik2000 [5.3K]
You add all the sides together, a good way to remember it is "perimeter, plus"
8 0
4 years ago
Read 2 more answers
Workland has a population of 10,000, of whom 7,000 work 8 hours a day to produce a total of 224,000 final goods. Laborland has a
kenny6666 [7]

Answer:

Workland has lower productivity but higher real GDP per person than Laborland.

Step-by-step explanation:

Consider the provided information.

Workland has a population of 10,000, of whom 7,000 work 8 hours a day to produce a total of 224,000 final goods.

Productivity = Output / Input

For Workland productivity is:

\frac{224,000}{7,000 \times 8}=\frac{224,000}{56,000}= 4

Laborland has a population of 5,000, of whom 3,000 work 7 hours a day to produce a total of 105,000 final goods.

For Laborland, productivity is:

\frac{105,000 }{3,000\times 7}=\frac{105,000 }{21,000 }= 5

Thus, Laborland has higher productivity .

To figure real GDP per person, divide output by population:

For Workland,

\frac{224,000}{10,000}= 22.4

for Laborland,

\frac{105,000 }{5,000 }= 21

Thus, Workland has a higher real GDP per person.

7 0
3 years ago
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