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maxonik [38]
2 years ago
8

Pmlease helppp tyyyy

Mathematics
1 answer:
Ainat [17]2 years ago
4 0

Answer:

Step-by-step explanation:

<h3>Solving quadratic equation using formula:</h3>

 5x² - 6x - 2 = 0

a = Coefficient of x² = 5

b = coefficient of x = -6

c = constant = -2

Discriminant = D = b² - 4ac

                           = (-6)² - 4 * 5 * (-2)

                           = 36 +  40

                           = 76  > 0

So, the quadratic equation has two distinct real roots.

\sf \boxed{\bf x = \dfrac{-b \± \sqrt{D}}{2a}}\\\\

     \sf = \dfrac{-[-6] \± \sqrt{76}}{2*5}\\\\= \dfrac{6 \±8.7}{10}\\\\=\dfrac{6+8.7}{10}  \ ; \ or \ x =\dfrac{6-8.7}{10}\\\\=\dfrac{14.7}{10} \ ; \ or \ x = \dfrac{-2.7}{10}

x = 1.47  or x = -0.27

Answer: x = 1.5 or (-0.3)

b) x² + 3x = 40

x² + 3x - 40= 0

We can solve the quadratic equation using factor method.

Sum = 3

Product = -40

Factors = 8 , (-5)

 When we add, 8 + (-5) = 3 , we get 5and when we multiply 8 *(-5) = -40, we get -(-40).

Rewrite the middle term of the quadratic equation using the factors.

 x² + 8x - 5x - 40 = 0

x(x + 8) - 5(x + 8)= 0

 (x + 8) (x - 5)    = 0

 x + 8 = 0   or x - 5 = 0

     x = -8   or       x = 5

Answer : x = -8 , 5

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of the 125 guests invited to a wedding ,104 attended the wedding .What percent of the invited guests attended the wedding
pashok25 [27]
\frac{104}{125} =\frac{104\times8}{125\times8}=\frac{832}{1000}

832/1000 = 0.832 = 0.832 * 100% = 83.2%

83.2% of the invited guests attended the wedding.

5 0
4 years ago
Two boards are placed end to end to make a walkway. One board is 5 feet 11 inches long, and the other board is 4 feet 6 inches l
Papessa [141]

Answer:

10 feet 5 inches long

Step-by-step explanation:

12 inches = 1 foot

11 inches + 6 inches = 17 inches = 1 foot 5 inches

1 foot 5 inches + 5 feet + 4 feet = 10 feet 5 inches

Therefore, the walking board is 10 feet 5 inches long

3 0
3 years ago
The earth has a mass of approximately 6\cdot 10^{24}6⋅10 24 6, dot, 10, start superscript, 24, end superscript kilograms (\text{
Alex_Xolod [135]

Answer:

0.02

Step-by-step explanation:

The volume of the earth's oceans is approximately 1.34\cdot 10^{9}1.34⋅10

9

1, point, 34, dot, 10, start superscript, 9, end superscript cubic kilometers (\text{km}^3)(km

3

)left parenthesis, start text, k, m, end text, cubed, right parenthesis, and ocean water has a mass of about 1.03 \cdot 10^{12}\,\dfrac{\text{kg}}{\text{km}^3}1.03⋅10

12

 

km

3

kg

​

1, point, 03, dot, 10, start superscript, 12, end superscript, start fraction, start text, k, g, end text, divided by, start text, k, m, end text, cubed, end fraction .

To simplify, we will use the product of powers property of exponents that says that x^a\cdot x^b = x^{a+b}x

a

⋅x

b

=x

a+b

x, start superscript, a, end superscript, dot, x, start superscript, b, end superscript, equals, x, start superscript, a, plus, b, end superscript.

\qquad 1.34\cdot 10^{9}\,\cancel{\text{km}^3} \cdot 1.03 \cdot 10^{12}\,\dfrac{\text{kg}}{\cancel{\text{km}^3}} = 1.3802 \cdot 10^{21}\,\text{kg}1.34⋅10

9

 

km

3

⋅1.03⋅10

12

 

km

3

kg

​

=1.3802⋅10

21

kg1, point, 34, dot, 10, start superscript, 9, end superscript, start cancel, start text, k, m, end text, cubed, end cancel, dot, 1, point, 03, dot, 10, start superscript, 12, end superscript, start fraction, start text, k, g, end text, divided by, start cancel, start text, k, m, end text, cubed, end cancel, end fraction, equals, 1, point, 3802, dot, 10, start superscript, 21, end superscript, start text, k, g, end text

Hint #2

Next we want to know what portion of the earth's mass this represents. We have:

\qquad \begin{aligned} \dfrac{\text{mass of the oceans}}{\text{total mass of the earth}} &= \dfrac{1.3802 \cdot 10^{21}\,\text{kg}}{6\cdot 10^{24}\,\text{kg}} \\\\ &= \dfrac{1.3802}{6\cdot 10^{3}} \\\\ &= \dfrac{1.3802}{6000} \\\\ &= 0.0002300\overline{3} \end{aligned}

total mass of the earth

mass of the oceans

​

​

 

=

6⋅10

24

kg

1.3802⋅10

21

kg

​

=

6⋅10

3

1.3802

​

=

6000

1.3802

​

=0.0002300

3

​

To convert this to a percent, we multiply by 100100100, so the oceans represent 0.02300\overline{3}\%0.02300

3

%0, point, 02300, start overline, 3, end overline, percent of the earth's total mass, according to these figures.

Hint #3

To the nearest hundredth of a percent, 0.020.020, point, 02 percent of the earth's mass is from oceans.

6 0
3 years ago
Find the missing lengths of the sides.
Anarel [89]

Given:

The figure of a right angle triangle.

a=b

Hypotenuse = 9\sqrt{2} in.

To find:

The missing lengths of the sides.

Solution:

In the given right angle triangle both legs a and b are equal, and hypotenuse is 9\sqrt{2} in.

Using Pythagoras theorem, we get

Hyponteuse^2=Base^2+Perpendicular^2

(9\sqrt{2})^2=(a)^2+(b)^2

81(2)=(a)^2+(a)^2                    [\because a=b]

81(2)=2(a)^2

Divide both sides by 2.

81=(a)^2

Taking square root on both sides.

\pm \sqrt{81}=a

\pm 9=a

Side cannot be negative. So,

9=a

Thus, the missing side lengths are a=9 in and b=9 in.

Therefore, the correct option is C.

6 0
3 years ago
What is the area of this trapezoid? Please help me
jenyasd209 [6]

Answer:

192

Step-by-step explanation:

both triangles are 12 in and the square is 168

so 12+12+168= 192in

3 0
3 years ago
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