1 answer:
The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>What is the area of the quadrilateral?</h3>
Herein we have a description of an <em>irregular</em> quadrilateral, whose area must be determined by adding the areas of minor quadrilaterals and triangles that are part of it. The area is now determined:
A = 0.5 · (24 cm) · (7 cm) + 0.5 · (15 cm) · (20 cm)
A = 234 cm²
The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>Remark</h3>
The picture with the quadrilateral is missing and is included as attachment.
To learn more on quadrilaterals: brainly.com/question/13805601
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Answer: (0,1)
Step-by-step explanation:
If and
are two point son a coordinate plane and (x,y) dividing it in a ratio of m: n.
Then , the coordinates of (x,y) is given by :-
Given : On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, - 3) and point B is at (- 4, 9).
Then , the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 :
Hence, the x- and y- coordinates of point E = (0,1)