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1 year ago

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Mathematics

1 answer:

ss7ja [257]1 year ago

5 0

The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)

<h3>What is the area of the quadrilateral?</h3>

Herein we have a description of an <em>irregular</em> quadrilateral, whose area must be determined by adding the areas of minor quadrilaterals and triangles that are part of it. The area is now determined:

A = 0.5 · (24 cm) · (7 cm) + 0.5 · (15 cm) · (20 cm)

A = 234 cm²

The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)

<h3>Remark</h3>

The picture with the quadrilateral is missing and is included as attachment.

To learn more on quadrilaterals: brainly.com/question/13805601

#SPJ1

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Step-by-step explanation:

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3 years ago

Noah and Lin are each trying to solve the equation x² - 6x + 10 = 0. They know that the solutions to x² = - 1 are i and -i, but

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Answer:

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Step-by-step explanation:

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$x^2 - 6x + 10 = 0\\x^2 - 6x = -10\\x^2 - 6x + 9 = -10 + 9\\(x-3)^2 = -1$

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2 years ago