1 answer:
The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>What is the area of the quadrilateral?</h3>
Herein we have a description of an <em>irregular</em> quadrilateral, whose area must be determined by adding the areas of minor quadrilaterals and triangles that are part of it. The area is now determined:
A = 0.5 · (24 cm) · (7 cm) + 0.5 · (15 cm) · (20 cm)
A = 234 cm²
The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>Remark</h3>
The picture with the quadrilateral is missing and is included as attachment.
To learn more on quadrilaterals: brainly.com/question/13805601
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Answer:
The distance between these two given points is:
Step-by-step explanation:
We are given two points:
(-3,7),(0,4)
<em>The distance between two points (a,b) and (c,d) is given by the distance formula as:</em>
<em></em>
similarly we can find the length of a line segment by considering the distance between the end points of the line segment.
So here (a,b)=(-3,7)
and (c,d)=(0,4).
Hence distance between these two points is given by: