Answer:
c. Compound 2 is more acidic because its conjugate base is more resonance stabilized
Explanation:
You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.
The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.
CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺
The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.
The molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bond is C₁₄H₂₀
<h3>Molecular formula</h3>
A formula that gives the number of atom of each element present in a one molecule or a compound.
<h3>Monocyclic hydrocarbons</h3>
The name of the saturated hydrocarbons formed by the name attaching the perfix cyclo to the name of acyclic unstaturated hydrocarbon
The molecular formula for a monocyclic hydrocarbon with 14 carbon and 2 triple bonds is C₁₄H₂₀
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