I believe it the answer is 3412
Answer:
O₂; KCl; 33.3
Explanation:
We are given the moles of two reactants, so this is a limiting reactant problem.
We know that we will need moles, so, lets assemble all the data in one place.
2KCl + 3O₂ ⟶ 2KClO₃
n/mol: 100.0 100.0
1. Identify the limiting reactant
(a) Calculate the moles of KClO₃ that can be formed from each reactant
(i)From KCl

(ii) From O₂

O₂ is the limiting reactant, because it forms fewer moles of the KClO₃.
KClO₃ is the excess reactant.
2. Moles of KCl left over
(a) Moles of KCl used

(b) Moles of KCl left over
n = 100.0 mol - 66.67 mol = 33.3 mol
Answer:
Molar mass and Mass
Explanation:
The relationship between mass and number of moles is given as;
Number of moles = Mass / Molar mass
Mass = 1.6 g
Molar mass of HCl = ( 1 + 35.5 ) = 36.5 g/mol
Number of moles = 1.6 g / 36.5 g/mol
Number of moles = 0.0438 mol
Answer:
Explain some of the uses of metals based on their properties.
Explanation:
Metals have a shiny or metallic luster and are good conductors of heat and electricity, they can be bent and pounded in various shapes, so they can be used on cars, coins, some pipes, keys, and and a flag.