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Iteru [2.4K]
3 years ago
7

Pedro bought 9 tickets to a basketball game. he paid a total of $189. enter an equation, using x as your variable, to determine

whether each ticket cost $21 or $28. then enter the cost of the ticket.
Mathematics
1 answer:
pychu [463]3 years ago
4 0
189 = 9x
x=21
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tamaranim1 [39]

The answer to that would be 30

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3 years ago
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Which is equivalent to 8X- Y + 3X
Zarrin [17]

Answer:

11x-y or 5x+y.

Step-by-step explanation: I hope this helps, I really don't know what the question means, since it not that specific.

6 0
3 years ago
Please I need some help!
Schach [20]

(f+g)(x) = 8x+2

(f-g)(x) = 4x-6

Step-by-step explanation:

Given

f(x) =6x-2\\g(x)=2x+4

we have to find

<u>a. (f+g)(x)</u>

(f+g)(x)=f(x)+g(x)\\=(6x-2)+(2x+4)\\=6x-2+2x+4\\=6x+2x-2+4\\=8x+2

<u>b. (f-g)(x)</u>

(f-g)(x)=f(x)-g(x)\\=(6x-2)-(2x+4)\\=6x-2-2x-4\\=6x-2x-2-4\\=4x-6

Hence,

(f+g)(x) = 8x+2

(f-g)(x) = 4x-6

Keywords: Functions, Operations on Functions

Learn more about functions at:

  • brainly.com/question/4021035
  • brainly.com/question/4034547

#LearnwithBrainly

7 0
3 years ago
Plz help I don’t know the answer
Rudiy27

Answer:

0.95

Step-by-step explanation:

8-3.25=4.75

4.75÷5=0.95

5 0
3 years ago
Binomial Probability
ASHA 777 [7]

Answer:

4.39% theoretical probability of this happening

Step-by-step explanation:

For each coin, there are only two possible outcomes. Either it lands on heads, or it lands on tails. The probability of a coin landing on heads is independent of other coins. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Theoretically, a fair coin

Equally as likely to land on heads or tails, so p = \frac{1}{2} = 0.5

10 coins:

This means that n = 10

What is the theoretical probability of this happening?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{10,2}.(0.5)^{2}.(0.5)^{8} = 0.0439

4.39% theoretical probability of this happening

6 0
3 years ago
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