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Olegator [25]
1 year ago
14

It took an hour to now a lawn using a mower with 14 inches blade. How long will it take using a mower with 12 inches wide

Mathematics
2 answers:
g100num [7]1 year ago
8 0

Answer:

70 mins

Step-by-step explanation:

This is called inverse proportion.

1hr : 14in

x hr : 12in

Ask yourself, what do you do to 14 to get 12? To find this out, we do:

14 / 12 = 1.16666667

Since the blade is smaller, it will take longer. So, we times 1hr by 1.16666667 to get

1.16666667 hrs =

1.17 hours (rounded)

This is 70.2 mins, or 1hr 10 mins

Hope this helps!

kozerog [31]1 year ago
7 0

If the time taken by 14 inches wide is one hour then the blade of 12 inches wide will take 1 hour 17 minutes to mow a lawn.

What is width?

The width of something is the measurement of one side of a body. It is generally less than length of that body or shape.

How to calculate time?

We have been given time of 1 hour if blade is 14 inches wide and we have to calculate time taken by 12 inches wide blade:

It will be as 14/12* 1 hour

=14/12

=1.167

=1.17 hour

Hence the time taken by the blade of 12 inches wide will be 1 hour and 17 minutes.

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X = 3y +9 <br>2x – 3y = 9<br>help plz​
Dominik [7]

Answer:

Their are caculators online search the type of math it is then put caculator for example exponents caculator

Step-by-step explanation:

6 0
3 years ago
David's money is three times Siti's money. Farid has RM 150 less than Siti. The total amount of their money is RM 2 000. How muc
mart [117]

Answer:

Siti's money = RM 430

David = RM 1,290

Farid = RM 280

Step-by-step explanation:

Let

Siti's money = x

David = 3x

Farid = x - 150

Total of their money = RM 2 000

x + 3x + (x - 150) = 2000

4x + x - 150 = 2000

5x = 2000 + 150

5x = 2,150

x = 2,150/5

x = RM 430

Siti's money = x

= RM 430

David = 3x

= 3(430)

= RM 1,290

Farid = x - 150

= 430 - 150

= RM 280

3 0
3 years ago
In a simple regression analysis for a given data set, if the null hypothesis β = 0 is rejected, then the null hypothesis ρ = 0 i
kati45 [8]

Answer:

Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0

The statistic to check the hypothesis is given by:

t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}

And is distributed with n-2 degrees of freedom

And the statistic to check the significance of a coeffcient in a regression is given by:

t_1 = \frac{\hat{\beta_1} -0}{S.E (\hat{\beta_1})}

For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:

Always

Step-by-step explanation:

In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:

Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0

The statistic to check the hypothesis is given by:

t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}

And is distributed with n-2 degrees of freedom

And the statistic to check the significance of a coeffcient in a regression is given by:

t_1 = \frac{\hat{\beta_1} -0}{S.E (\hat{\beta_1})}

For this case is importantto remember that t1 and p value for test of slope coefficient is the same test statistic and p value for the correlation test so then the answer would be:

Always

4 0
3 years ago
Rectangle area w algebra<br> step by step explanation please :)
Natalija [7]

We know that the area is 20.

Since 20 is a small number: lets list out possible combinations of lengths and widths.

1 * 20

2 * 10

4 * 5

L = 7 + 3w

lets see which on makes sense.

L = 7 + 3w

20 = w7 + 3w^2

3w^2 + 7w -20 = 0

(3w - 10)(w - 2)

w can equal 10/3 or 2.

So the dimensions: are Width = 2 Length = 10

8 0
3 years ago
Complete the table for the radioactive iotope. (Round your anwer to 2 decimal place. Iotope : 239 Pu
Marizza181 [45]

If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams

The half life in years = 24100

Consider the quantity of the radio active isotope remaining

y = Ce^{kt}

When t = 1000 the y = 1.2

y = C/2 when t = 1599

Substitute the values in the equation

C/2 = Ce^{24100k}

Cancel the C in both side

1/2 = e^{24100k}

Here we have to apply ln to eliminate the e terms

ln (1/2) = 24100k

k = ln(1/2) / 24100

k = -2.87× 10^-5

To find the initial value we have to substitute the value of k and y in the equation

1.2 = Ce^{1000 ×  -2.87× 10^-5}

C = 1.2 / e^(-0.0287)

C = 2.16 gram

Hence, the initial quantity of the radioactive isotope is 2.16 gram

Learn more about half life here

brainly.com/question/4318844

#SPJ4

7 0
1 year ago
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