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11 months ago

in the rhombus shown below AC and BD are 6 and 4in respectively determine the area of the figure in square inches

Mathematics

1 answer:

bulgar [2K]11 months ago

7 0

The area of a rhombus is computed as follows:

A = p*q*1/2

where p and q are the diagonals of the rhombus.

In this case:

A = AC*BD*1/2

A = 6*4*1/2

A = 12 square inches

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Step-by-step explanation:

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2 years ago

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DochEvi [55]

Answer:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

This tells us that:

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Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

$c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$ .

So we want to find a way to express this as:

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So we can write this as:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

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2 years ago

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Alex777 [14]

Answer:

$dAB=10\ units$

Step-by-step explanation:

we know that

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The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$