1) This is a Two tailed Test.
2) Decision rule is; If the p-value is greater than 4% fail to reject H₀.
3) P-value = 0.00968764 and so we reject H₀
<h3>How to state the decision rule in hypothesis testing?</h3>
We are given the hypothesis as;
Null Hypothesis; H₀: m₁ = m₂
Alternative Hypothesis; H₁: m₁ ≠ m₂
1) Since the alternative hypothesis has "not equal to sign", then it is a two tailed test.
2) Since we are told to use significance level as 0.04, then we can say that the decision rule is;
If the p-value is greater than 4% fail to reject H₀.
3) Using a 2-Sample Z-Test online TI calculator gives the test statistic as;
z = 2.5868
4) From z-score calculator, p-value equals 0.00968764. This is less than 0.04 and as such the decision regarding H₀ is to reject H₀.
5) P-value = 0.00968764
Read more about decision rule in Hypothesis Testing at; brainly.com/question/17192140
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