The distance of separation between the lenses is determined as 12 cm.
The distance of the image formed by the first lens is calculated as follows;
1/d₁ = 1/f - 1/di₀
1/di₁ = 1/4 - 1/12
1/di₁ = 2/12
1/di₁ = 1/6
di₁ = 6 cm
Use magnification formula as shown below;
M = (di₁di₂)/(d₀₁d₀₂)
1 = (di₁di₂)/(d₀₁d₀₂)
di₂ = (d₀₁d₀₂)/(di₁)
di₂ = (12 x d₀₂)/(6)
di₂ = 2d₀₂
1/f = 1/ d₀₂ + 1/di₂
1/f = 1/ d₀₂ + 1/2d₀₂
1/f = 1.5/d₀₂
d₀₂ = 1.5f
d₀₂ = 1.5(4 cm) = 6 cm
D = di₁ + d₀₂
D = 6 cm + 6 cm
D = 12 cm
Thus, the distance of separation between the lenses is determined as 12 cm.
Learn more about distance between lens here: brainly.com/question/12993552
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Potential Energy (P.E) = Mass x
Acceleration due to Gravity x Altitude. Putting this value in the above equation we get, Dimensional Formula of
Potential energy= M1L2T-2.
Answer:
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