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Svetradugi [14.3K]
2 years ago
13

A converging lens with a focal length of 4.0 cm is to the left of a second identical lens. When a feather is placed 12 cm to the

left of the first lens, the final image is the same size and orientation as the feather itself. What is the separation between the lenses?​
Physics
1 answer:
frez [133]2 years ago
5 0

The distance of separation between the lenses is determined as 12 cm.

<h3>Distance of image formed by the first lens</h3>

The distance of the image formed by the first lens is calculated as follows;

1/d₁ = 1/f - 1/di₀

1/di₁ = 1/4 - 1/12

1/di₁ = 2/12

1/di₁ = 1/6

di₁ = 6 cm

<h3>Find the final position of the image</h3>

Use magnification formula as shown below;

M = (di₁di₂)/(d₀₁d₀₂)

1 = (di₁di₂)/(d₀₁d₀₂)

di₂ = (d₀₁d₀₂)/(di₁)

di₂ = (12 x d₀₂)/(6)

di₂ = 2d₀₂

1/f = 1/ d₀₂ + 1/di₂

1/f =  1/ d₀₂ + 1/2d₀₂

1/f = 1.5/d₀₂

d₀₂ = 1.5f

d₀₂ = 1.5(4 cm) = 6 cm

<h3>Distance between the two converging lens</h3>

D = di₁ + d₀₂

D = 6 cm + 6 cm

D = 12 cm

Thus, the distance of separation between the lenses is determined as 12 cm.

Learn more about distance between lens here:  brainly.com/question/12993552

#SPJ1

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Answer: the lattice contains 1 magnesium ion for every 2 fluoride ions.

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7 0
3 years ago
A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary
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The distance traveled by the wood after the bullet emerges is 0.16 m.

The given parameters;

  • <em>mass of the bullet, m = 23 g = 0.023 g</em>
  • <em>speed of the bullet, u = 230 m/s</em>
  • <em>mass of the wood, m = 2 kg</em>
  • <em>final speed of the bullet, v = 170 m/s</em>
  • <em>coefficient of friction, μ = 0.15</em>

The final velocity of the wood after the bullet hits is calculated as follows;

m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\0.023(230) + 2(0) = 0.023(170) + 2v_2\\\\5.29 = 3.91 + 2v_2\\\\2v_2 = 1.38\\\\v_2 = \frac{1.38}{2} = 0.69 \ m/s

The acceleration of the wood is calculated as follows;

\mu = \frac{a}{g} \\\\a = \mu g\\\\a = 0.15 \times 9.8\\\\a = 1.47 \ m/s^2

The distance traveled by the wood after the bullet emerges is calculated as follows;

v^2 = v_0^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\s = \frac{v^2}{2a} \\\\s = \frac{(0.69)^2}{2(1.47)} \\\\s = 0.16 \ m

Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.

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Answer:

C. Code of ethics

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I don't completely understand your drawing, although I can see that you certainly
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That's all there is to a 'moment'.

The lever (or the see-saw) is balanced when (the sum of all the moments
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