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3 years ago

Which of these hazmat products are allowed in your FC?

Physics

1 answer:

aliina [53]3 years ago

7 0

Answer: Hazmat products are allowed in your FC are:

A GPS unit (lithium batteries)
A subwoofer (magnetized materials)

Explanation:

Hazmat products consist of flammable, corrosive and harmful substances which are actually very hazardous to human health and environment.

Hazardous material allowed in FC are as follows.

Magnetized material products like as speakers.
Non-spillable battery products like toy cars.
Lithium-ion battery containing products like laptops, mobile phones etc.
Non-flammable aerosol.

So, hazmat allowed products are GPS unit (lithium batteries) and subwoofer (magnetized materials).

Thus, we can conclude that hazmat products are allowed in your FC are:

A GPS unit (lithium batteries)
A subwoofer (magnetized materials)

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The gravitational potential has a zero value gravitational field in the same place is? Maximum or null indeterminate

DedPeter [7]

Answer:maximum

Explanation:

8 0

3 years ago

Some car manufacturers claim that their vehicles could climb a slope of 42 ∘. For this to be possible, what must be the minimum

Paladinen [302]

Answer:

D. 0.9

Explanation:

Calculating minimum coefficient of static friction, we first resolve the forces (normal and frictional) acting on the vehicle at an angle to the horizontal into their x and y components. After this, we can now substitute the values of x and y components into equation of static friction. Diagrammatic illustration is attached.

Resolving into x component:

∑ $F_{x} = F_{s} - mgsin\alpha =0$

$F_{s} = mgsin\alpha$ ------(1)

Resolving into y component:

∑ $F_{y} = F_{n} - mgcos\alpha =0$

$F_{n} = mgcos\alpha$ ------(2)

Static frictional force, $F_{s} \leq$ μ $F_{n}$ ------(3)

substituting $F_{s}$ from equation (1) and $F_{n}$ from equation (2) into equation (3)

$mgsin\alpha \leq$ μ $mgcos\alpha$

$sin\alpha \leq$ μ $cos\alpha$

μ $\geq \frac {sin\alpha}{cos\alpha}$

μ $\geq tan\alpha$

The angle the vehicles make with the horizontal α = 42°

μ ≥ tan 42°

μ ≥ 0.9

6 0

3 years ago

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 78.5 m/s. Th

Andrews [41]

Answer:

FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

Explanation:

First you have to consider that the Ford Thunderbird (FT) follows a rectilinear motion with varying acceleration, while Mercedez Benz (MB) has a constant velocity (no acceleration). So if you finde the time spent by FT in each section, and the distance, then you will find the distance for MB.

1) Vf² = Vi² + 2ad, where Vf: final velocity, Vi: ionitial velocity, a: acceleration and d: distance.

For the first portion (0 m/s)² = (78.5 m/s)² + 2a(250 m) ⇒

-(78.5 m/s)² / 2(250m) = a ⇒ a = -12.3 m/s².

Now, you can find the corresponding time for this section with the following formule: Vf = Vi + at ⇒ 0 m/s = 78.5 m/s + (-12.3 m/s²) t

⇒ t= (-78.5 m/s)/ (-12.3 m/s²) ⇒ t= 6.4 seconds.

2) Then FT spent 5 seconds in the pit.

3) The the FT accelerates until reach 78.5 m/s again in a distance of 370 m.

Vf² = Vi² + 2ad ⇒ (78.5 m/s)² = (0 m/s)² + 2a(370 m)

⇒ (78.5 m/s)²/ 2(370 m) = a ⇒ a = 8.3 m/s²

Then, Vf = Vi + at ⇒ 78.5 m/s = 0 m/2 + (8.3 m/s²) t

⇒ (78.5 m/s)/(8.3 m/s²) = t ⇒ t = 9.5 seconds.

4) Summarizing, the FT moves 620 meters (250 + 370 mts) in 20.9 seconds ( 6.4 s + 5 s + 9.5 s).

5) During this time, MB moves

Velocity = distance/ time ⇒ Velocity x time = Distance

⇒ Distance = (78.5 m/s) x (20.9 seconds) ⇒ Distance = 1640.6 meters

6) Finally, the FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

3 0

3 years ago

A negative charge in a cloud induces a positive charge in the ground below the cloud. The charges gradually increase. Then the a

Nataly [62]

A. static discharge <span>Static discharge is the sudden flow of electricity between two electrically charged objects caused by contact, an electrical short, or dielectric breakdown.</span>

3 0

3 years ago

Read 2 more answers

A pilot is flying from DFW to NYC. The air traffic controller directs him to fly 69° Northeast at 243 m/s. What is the y compone

kolezko [41]

Answer:

$v_{y} = 227$ m/s

Explanation:

Assumptions: 0° is true North, and 90° is east (along the x-axis).

To solve this problem we must use the expression:

$v_{y} = v_{0}sin(\theta)$

Where $v_{y}$ is the velocity in the y-direction (East), $v_{0}$ is the total velocity in the direction which the aircraft is travelling, and $\theta$ is the direction the aircraft is travelling (angle from the y-axis).

Using the equation above, we obtain the y-component of velocity

$v_{y} = (243)sin(69) = 226.86...$ m/s which is rounded to 227 m/s (due to the number of significant figures in the question).

8 0

4 years ago