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KiRa [710]
3 years ago
10

What are successfulness of the Competition policy in South Africa?​

Physics
1 answer:
Mars2501 [29]3 years ago
6 0

Answer:

The product choices along with its competitive prices were provided to the consumers. Practices such as horizontal collusion and resale price maintenance was declared unlawful in 1984. Prevention of monopoly growth was the aim of the competition policy act.

Explanation:

hope this helps you

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To determine a waves' frequency, you must know the
kykrilka [37]
B. number of oscillations in a given period of time.
7 0
4 years ago
Read 2 more answers
What would be the distance moved if we had a 70 n force and work done is 8j
Lostsunrise [7]

Answer:

0.1143m

Explanation:

W=f×s

8=70s

make s the subject of the formula

s=8/70

=0.1143m

3 0
3 years ago
You pull on a spring whose spring constant is 22 N/m, and stretch it from its equilibrium length of 0.3 m to a length of 0.7 m.
Liono4ka [1.6K]

Answer:

W= 4.4 J

Explanation

Elastic potential energy theory

If we have a spring of constant K to which a force F that produces a Δx deformation is applied, we apply Hooke's law:

F=K*x  Formula (1): The force F applied to the spring is proportional to the deformation x of the spring.

As the force is variable to calculate the work we define an average force

F_{a} =\frac{F_{f}+F_{i}  }{2}  Formula (2)

Ff: final force

Fi: initial force

The work done on the spring is :

W = Fa*Δx

Fa : average force

Δx :  displacement

W = F_{a} (x_{f} -x_{i} )   :Formula (3)

x_{f} :  final deformation

x_{i}  :initial deformation

Problem development

We calculate Ff and Fi , applying formula (1) :

F_{f} = K*x_{f} =22\frac{N}{m} *0.7m =15.4N

F_{i} = K*x_{i} =22\frac{N}{m} *0.3m =6.6N

We calculate average force applying formula (2):

F_{a} =\frac{15.4N+6.2N}{2} = 11 N

We calculate the work done on the spring  applying formula (3) :         :

W= 11N*(0.7m-0.3m) = 11N*0.4m=4.4 N*m = 4.4 Joule = 4.4 J

Work done in stages

Work is the change of elastic potential energy (ΔEp)

W=ΔEp

ΔEp= Epf-Epi

Epf= final potential energy

Epi=initial potential energy

E_{pf} =\frac{1}{2} *k*x_{f}^{2}

E_{pi} =\frac{1}{2} *k*x_{i}^{2}

E_{pf} =\frac{1}{2} *22*0.7^{2} = 5.39 J

E_{pf} =\frac{1}{2} *22*0.3^{2} = 0.99 J

W=ΔEp=  5.39 J-0.99 J = 4.4J

:

4 0
3 years ago
An electric toaster has a power rating of 1100 W at 110 V. What is the resistance of the heating coil?
Semmy [17]

 R = 11 ohms

Explanation:

Given parameters:

Power of the electric toaster = 1100W

Voltage = 110V

Unknown:

Resistance, R of the heating coli = ?

Solution:

Electric power is given as:

     Electric power = IV

where:

  I is the current

  V is the voltage

       According to Ohm's law, V = IR

 where R is the resistance. If we make current the subject of the formula and substitute, it gives:

                  Power = \frac{[tex]V^{2}}{R}[/tex]

  Power =  \frac{[tex]110^{2}}{R}[/tex]

     R = \frac{Power }{[tex]110^{2}}[/tex] =  \frac{1100 }{[tex]110^{2}}[/tex]

   R = 11 ohms

learn more:

Power supply brainly.com/question/4322575

#learnwithBrainly

3 0
3 years ago
At one instant, an object moving downward in free fall on the Earth has a speed of 50 m/s. Its speed 1 second later is
maksim [4K]

Answer:

velocity 1 second later = 59.8 m/s

Explanation:

Velocity final = Velocity initial + acceleration • time

Velocity final = 50m/s + 9.8m/s/s • 1s

Velocity final = 59.8 m/s

4 0
2 years ago
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