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3 years ago

How are the wavelength and frequency of electromagnetic waves related to their energy

Physics

1 answer:

777dan777 [17]3 years ago

3 0

As wavelength decreases, frequency increases, but as frequency decreases, wavelength increases...Vice-Versa

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You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between

Klio2033 [76]

Answer:

a) $u=0.05602\ m.s^{-1}$

b) $u'=0.0169\ m.s^{-1}$

Explanation:

Given:

mass of the ball, $m=0.4\ kg$

horizontal velocity of the ball, $u=10\ m.s^{-1}$

mass of the person, $M=71\ kg$

<u>Using the law of conservation of momentum:</u>

$m.v=(M+m).u$

$0.4\times 10=(71+0.4)\times u$

$u=0.05602\ m.s^{-1}$

Given:

rebound velocity of the ball, $v'=7\ m.s^{-1}$

Using conservation of momentum,

$m.v+M.u=m.v'+M.u'$

$0.4\times10+71\times 0=0.4\times 7+71\times u'$

$u'=0.0169\ m.s^{-1}$

4 0

3 years ago

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During spring tide, the sun and moon are aligned. Which statement below best describes the tidal range during a spring tide?

e-lub [12.9K]

Answer:

Explanation:

A ) The smallest tidal ranges are less than 1 m (3 feet). The highest tides, called spring tides, are formed when the earth, sun and moon are lined up in a row. This happens every two weeks during a new moon or full moon. Smaller tides, called neap tides, are formed when the earth, sun and moon form a right angle.

C ) The most extreme tidal range occurs during spring tides, when the gravitational forces of both the Moon and Sun are aligned (syzygy), reinforcing each other in the same direction (new moon) or in opposite directions (full moon).

4 0

3 years ago

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Ms. Paul is standing at the top of a cliff that is 100 m tall. She kicks a rock and it gets a horizontal velocity of 15.0 m/s. D

Lynna [10]

vertical motion

h=1/2 gt²

100 = 1/2 x 10 x t²

t² = 100/5 = 20

t = 2√5 s

horizontal motion

x = v.t

x = 15 x 2√5

x = 30√5 m

3 0

2 years ago

The given function represents the position of a particle traveling along a horizontal line. s(t) = 2t3 − 3t2 − 36t + 6 for t ≥ 0

igor_vitrenko [27]

1) The velocity of the particle is given by the derivative of the position. So, if we derive s(t), we get the velocity of the particle as a function of the time:

$v(t)=s'(t)=(2t^3-3t^2-36t+6)'=6t^2-6t-36$

2) The acceleration of the particle is given by the derivative of the velocity. So, if we derive v(t), we get the acceleration of the particle as a function of the time:

$a(t)=v'(t)=(6t^2-6t-36)'=12t-6$

8 0

3 years ago

The potential energy of a 40-kg cannon ball is 14000 J. How high was the cannon ball to have this much potential energy?

nasty-shy [4]

Pe = mgh.
14000 J = (40kg)(10m/s^2)(h)
h = 35 meters

7 0

3 years ago

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