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3 years ago

Static electricity is the

Physics

2 answers:

guapka [62]3 years ago

4 0

Unlike charges attracting each other

Galina-37 [17]3 years ago

4 0

A. Unlike charges attracting eachother

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In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 1

asambeis [7]

Explanation:

It is given that,

Frequency of monochromatic light, $f=5\times 10^{14}\ Hz$

Separation between slits, $d=2.2\times 10^{-5}\ m$

(a) The condition for maxima is given by :

$d\ sin\theta=n\lambda$

For third maxima,

$\theta=sin^{-1}(\dfrac{n\lambda}{d})$

$\theta=sin^{-1}(\dfrac{nc}{fd})$

$\theta=sin^{-1}(\dfrac{3\times 3\times 10^8\ m/s}{5\times 10^{14}\ Hz\times 2.2\times 10^{-5}\ m})$

$\theta=4.69^{\circ}$

(b) For second dark fringe, n = 2

$d\ sin\theta=(n+1/2)\lambda$

$\theta=sin^{-1}(\dfrac{5\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{5c}{2df})$

$\theta=sin^{-1}(\dfrac{5\times 3\times 10^8}{2\times 2.2\times 10^{-5}\times 5\times 10^{14}})$

$\theta=3.90^{\circ}$

Hence, this is the required solution.

8 0

2 years ago

3x - 4 > 4x - 8 simplify

Anit [1.1K]

Answer:

Explanation:

<u>Inequalities</u>

The inequalities relate expressions using signs different from the equal sign, like "<" or "<" among others.

They can be treated as a normal equation but in case of directional relationals, care must be taken when multiplying or dividing by negative numbers.

The inequality given in the question is

3x - 4 > 4x - 8

Subtracting 3x in both sides

3x - 4 -3x > 4x - 8 -3x

Simplifying

-4 > x - 8

Adding 8

-4 + 8 > x - 8 + 8

Simplifying

4 > x

The solution comes by flipping both sides and the inequality sign

x < 4

7 0

2 years ago

Can someone please help me with this

SashulF [63]

There’s no picture or question

3 0

2 years ago

why do we not notice a difference in the fall and winter in the amount of oxygen in the air even when leaves fall off

sveticcg [70]

Earths tilt making the sun go haywire lol XD

6 0

3 years ago

A straight wire of length 0.53 m carries a conventional current of 0.2 amperes. What is the magnitude of the magnetic field made

olga55 [171]

Explanation:

It is given that,

Length of wire, l = 0.53 m

Current, I = 0.2 A

(1.) Approximate formula:

We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m

The formula for magnetic field at some distance from the wire is given by :

$B=\dfrac{\mu_oI}{2\pi r}$

$B=\dfrac{4\pi \times 10^{-7}\times 0.2\ A}{2\pi \times 0.02\ m}$

B = 0.000002 T

$B=10^{-5}\ T$

(2) Exact formula:

$B=\dfrac{\mu_oI}{2\pi r}\dfrac{l}{\sqrt{l^2+4r^2} }$

$B=\dfrac{\mu_o\times 0.2\ A}{2\pi \times 0.02\ m}\times \dfrac{0.53\ m}{\sqrt{(0.53\ m)^2+4(0.02\ m)^2} }$

B = 0.00000199 T

B = 0.000002 T

Hence, this is the required solution.

4 0

3 years ago