Answer:
6, 2, 2/3, 2/9, 2/27, 2/81
Step-by-step explanation:
The nth term of a geometric progression is expressed as;
Tn = ar^n-1
a is the first term
n is the number of terms
r is the common ratio
Given
a = 6
r = 1/3
when n = 1
T1 = 6(1/3)^1-1
T1 = 6(1/3)^0
T1 = 6
when n = 2
T2= 6(1/3)^2-1
T2= 6(1/3)^1
T2 = 2
when n = 3
T3 = 6(1/3)^3-1
T3= 6(1/3)^2
T3= 6 * 1/9
T3 = 2/3
when n = 4
T4 = 6(1/3)^4-1
T4= 6(1/3)^3
T4= 6 * 1/27
T4 = 2/9
when n = 5
T5 = 6(1/3)^5-1
T5= 6(1/3)^4
T5= 6 * 1/81
T5 = 2/27
when n = 6
T6 = 6(1/3)^6-1
T6= 6(1/3)^5
T6= 6 * 1/243
T6 = 2/81
Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81
Given:
Monthly fees for the local pool are $8 per month and $2 per visit.
Hector pays $34 in pool fees total for the month.
To find:
The number of times he visit the pool.
Solution:
We have,
Monthly fee of pool = $8
Additional fee = $2 per visit
Let Hector visit x times.
Additional fee for x times = $2x
Total fee = Monthly fee + Additional fee
Divide both sides by 2.
Therefore, Hector visit the pool 13 times.
The mnemonic SOH CAH TOA helps you remember the relevant trig relationship is
Sin(α) = Opposite/Hypotenuse
sin(α) = (1 ft)/(14 ft)
α = arcsin(1/14) ≈ 4°
The angle the ramp makes with the sidewalk is 4°.
Answer:
which question? you want me to answer
Step-by-step explanation:
Just substitute in the number 3 for x then subtract 3 at both sides and youll have y=7
