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horrorfan [7]
2 years ago
9

A 845 mL NaCl solution is diluted to a volume of 1.19 L and a concentration of 6.00 M . What was the initial concentration? Expr

ess your answer with the appropriate units. chegg
Chemistry
1 answer:
marysya [2.9K]2 years ago
7 0

The initial concentration was 8.45M

Step 1: Given data

Initial concentration (C₁): ?

Initial volume (V₁): 635 mL = 0.845 L

Final concentration (C₂): 6.00 M

Final volume (V₂): 1.19 L

Step 2: Calculate the initial concentration

We have a concentrated NaCl solution and we want to prepare a diluted one. We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₁ = C₂ × V₂  / V₁

C₁ = 6.00 M × 1.19 L  / 0.845 L

C₁ = 8.45 M

Thus, The initial concentration was 8.45M

Learn more about concentration here:

brainly.com/question/10725862

#SPJ4

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<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

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What determines an element's chemical properties
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The three factors determine the chemical properties of an element:
<span><span>The number and arrangement of electrons in an atom
</span><span>The number of valence electrons
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Read 2 more answers
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Answer:

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Explanation:

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joja [24]

Answer:

The answer to your question is 2 molecules, or B(edg 2021).

Explanation:

edg 2021

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Draw a Lewis structure for HCCl3 . Include all hydrogen atoms and show all unshared pairs and the formal charges, if any. Assume
andrey2020 [161]

Answer:

See answer below

Explanation:

First, let's explain what a Lewis structure is.

A lewis structure in short words is a draw of an atom or molecule showing how the electrons bond with another electrons of atoms, and also shows the unshared pair of electrons, which are the electrons that do not bond in the molecule. In the case of an atom, it shows all the available electrons it has to be shared and bonded with another atom to form a molecule.

With this said, in order to draw the lewis structure we need to know how many electrons the atoms involved have. To know this, we need to write the electronic configuration of the atoms, based on it's atomic number.

In the case of Hydrogen (Z = 1), Carbon (Z = 6) and Cl (Z = 17):

[H] = 1s¹     1 electron available.

[C] = 1s² 2s² 2p²   In this case, we have 4 electrons.

[Cl] = 1s² 2s² 2p⁶ 3s² 3p⁵  In this case, 7 electrons.

Now that we have the configuration, and the available electrons, we need to draw the atoms. The Carbon is the more electronegative atom of them, so, the bonding will be formed based on this atom as the central. So the other atoms will just bond and shared a pair of electron with the carbon. The HCCl₃ can be treated as CH₄, with a tetrahedrical form.

The picture below shows the lewis structure.

Hope this helps

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