Answer:
Density = 11.4 g/cm³
Explanation:
Given data:
Density of lead = ?
Height of lead bar = 0.500 cm
Width of lead bar = 1.55 cm
Length of lead bar = 25.00 cm
Mass of lead bar = 220.9 g
Solution:
Density = mass/ volume
Volume of bar = length × width × height
Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm
Volume of bar = 19.4 cm³
Density of bar:
Density = 220.9 g/ 19.4 cm³
Density = 11.4 g/cm³
Metals such as iron, nickel and cobalt are detected by passive and active metal detectors. Other metals, such as copper, brass and aluminum, are detected only by active means.
Answer:
i dont know but it is probily 4 and 6
There are 27.67834 g/mol in 3.73 moles of lioh
Answer:
Explanation:
Reaction of hydrazine is
N2H4 + O2 --> N2 + 2H2O
Mass of hydrazine mole = 14x2 + 1x4 = 32g/Mol
Mass of O2 mole = 16x2 = 32g/Mol
Number of moles in 2.29kg of hydrazine
2290/32=71.56Moles
1mol of hydrazine required to react with 1mol of O2
Amount of O2 required to react with hydrazine
71.56*32=2290
Required O2 amount is exactly the same.
Therefore limiting reactant is hydrazine and excess of 850g of O2 will be in excess.
