you have to show us the rest of it because we have no idea what your looking at. I'm sorry
Answer:
0.053 L is the volume of concentrated solution that was used
Explanation:
Let's determine the answer of this, by rules of three.
There is also a dilution formula.
Molarity is a sort of concentration that indicates the moles of solute in 1L of solution.
In 1 L of concentrated solution, there are 1.5 moles of NaCl
In 1 L of diluted solution, there are 0.80 moles.
The volume for the diluted solution is 0.10L
The rule of three will be:
1L of solution has 0.80 moles of solute
Then, 0.10L of solution must have (0.1 . 0.8)/1 = 0.08 moles
This moles came from the concentrated solution, and we know that in 1L of this solution we have 1.5 moles. Therefore the rule of three will be:
1.5 moles are in 1L of solution
0.08 moles were in (0.08 . 1L / 1.5) = 0.053 L (This is the volume of concentrated solution that was used)
Dilution formula is: M conc . Vol conc = M diluted . Vol diluted
1.5 M . Vol conc = 0.80 M . 0.10L
Vol conc = 0.80 M . 0.10L / 1.5M = 0.053L
Answer:

Explanation:
<em>Ferrous Sulphate</em>
<em> is generally found as Lime-Green Crystals. On heating, these crystals almost immediately turn white-yellow. They then, break down to produce an anhydrous mixture of Sulphur Trioxide </em>
<em>, Sulphur Dioxide </em>
<em> as well as Ferric Oxide </em>
<em>.</em>
<em>We can hence, frame a skeletal equation of this reaction and try to balance it.</em>
<em>Hence,</em>

<em>Now,</em>
<em>a)In order to balance it through the 'Hit &Trial Method', we'll follow a series of </em><em>steps</em><em>:</em>
<em>1. First, lets compare the number of Fe (Iron) atoms on the RHS and LHS. We find that, the no. of Fe Atoms on the RHS is twice the number of Fe Atoms on the LHS. We hence, add a co-effecient 2 beside </em>
.
<em>2. Now, Iron atoms, Sulphur Atoms and Oxygen atoms occur 2, 2, 8 respectively on both the sides:</em>
<em> Hence, As all the other elements as well as iron, balance, we've arrived upon our Balanced Equation :</em>
<em> </em>
<em>b) We know that, decomposition reactions are [generally] endothermic reactions in which Large Compounds </em><em>decompose </em><em>into smaller elements and compounds. Here, as Ferrous Sulphate </em><em>decomposes </em><em>into Sulphur Dioxide, Sulphur Trioxide and Ferric Oxide, the reaction that occurs here is </em><em>Decomposition Reaction.</em>