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LenKa [72]
2 years ago
13

Consider two copper wires. one has twice the length and twice the cross-sectional area of the other. how do the resistances of t

hese two wires compare?
Physics
1 answer:
Anestetic [448]2 years ago
5 0

Answer:

R = ρ L / A     where R is the resistance and ρ the resistivity:

R2 / R1 = (L2 / A2) / (L1 / A1) = L2 * A1 / (L1 * A2)

R2 / R1 =  (2 L * A) / (L * 2 A) = 1

Their resistances should be the same.

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Rudiy27

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