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Anarel [89]
3 years ago
14

A student needs to prepare 100.0 mL of vitamin C solution according to the directions in Part 1 of the experiment. S/he weighs o

ut 0.0499 g vitamin C (molar mass = 176.124 g/mol) and dissolves it in water to give 100.0 mL solution. S/he pipets 10.00 mL of the solution into a beaker and adds 20 mL of water and 10 mL of buffer. (a) How many mg of vitamin C are in the beaker?
Physics
1 answer:
Rudiy273 years ago
4 0

Answer:

4.99 mg of vitamin C are in the beaker.

Explanation:

Given that,

Weight of vitamin = 0.0499 g

Molar mass = 176.124 g/mol

Weight of water = 100.0 ml

We need to calculate the mg of vitamin C in the beaker

We dissolve 0.0499 g vitamin C in water to from 100.0 ml solution.

100 ml solution contain 49.9 mg vitamin C

Now, we take 10 ml of this vitamin C solution in breaker

Since, 100 ml solution =49.9 mg vitamin C

Therefore,

10\ ml\ solution =\dfrac{10\times49.9}{100}

10\ ml\ solution =4.99\ mg

Hence, 4.99 mg of vitamin C are in the beaker.

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Heat given to the system = Q = +658 J.

According to the first law of thermodynamics, 
ΔE = Q + W
178 = 658 + W 
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Minus sign indicates that work is done by the system. 
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3 years ago
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A spy in a speed boat is being chased down a river by government officials in a faster craft. Just as the officials’ boat pulls
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Answer:

They are 7.4m apart.

Explanation:

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Because we have a contant velocity motion on X axis:

xs=vs*t\\xs=17m/s*(0.68s)\\xs=11.6m

and

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the distance between them is given by:

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7 0
3 years ago
A cat dozes on a stationary merry-go-round, at a radius of 4.6 m from the center of the ride. then the operator turns on the rid
ioda
<span>Radius = 4.6 m
 Time for one complete rotation t = 5.5 s.
 Distance = 2 x 3.14 x R = 2 x 3.14 x 4.6 m = 28.888.
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Which one of the following substances is a liquid fuel used in rocket engines?
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The answer is, "B", "Ammonia".
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You used the right-hand rule to determine the z component of the angular momentum, but as a check, calculate in terms of positio
KengaRu [80]

Answer:

case x py   L is in the positive z direction

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Explanation:

The angular amount is defined by the relation

         L = r x p

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The module of this vector can be concentrated by the relation

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in the case x py

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