To answer, determine the amount of paint that is needed in order to cover the whole of the sign. If we use the ratio and proportion and letting x be the unknown amount. The equation would be,
1/2 / 1/3 = x / 1
The value of x from the equation is equal to 1.5. Thus, the answer is letter D. 3/2 cups.
So j completed 6/7 of a lap
gabe has completed 2/9 lap
so
1 j lap=7 mins s o
7j
j=num of laps
1 g lap=9 mins so
9g
g=num of laps
then 6+j
and g+2
so
when will the times be equal
7j+6=9g+2
subtract 2 from both sides
7j+4=9g
divide both sides by 9
7/9j+4/9=g
so to get a whole number of laps, we must subsitute a number when it is multiplied by 7 then add 4, we get a multiplue of 9
so if j=2
7/9(2)+4/9=g=14/9+4/9=g=18/9=g=2
so josh and gabe must run 2 lap each because
6+(2 times 7)=2+(9 times 2)
6+14=2+18
20=20
true so
the answer is 2 laps
<span>0.05 arc-second = 1 degree/72000 = (pi
radians)/(180*72000) = 2.424 x 10^(-7) radians</span>
<span>The distance is roughly: </span>
<span>R*(theta) = (600 light-years)*2.424 x 10^(-7) = 0.00014544 light-years = 1.275
light-hours = (3600 seconds)*(3 x 10^8 m/s)*(1.275) = 1.38 x 10^12 meters.</span>
Answer:
890 beads can be fitted in the triangular prism.
Step-by-step explanation:
If we can fill the spherical beads completely in the triangular prism,
Volume of the triangular prism = Volume of the spherical beads
Volume of triangular prism = Area of the triangular base × Height
From the picture attached,
Area of the triangular base = ![\frac{1}{2}(\text{Base})(\text{Height})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BBase%7D%29%28%5Ctext%7BHeight%7D%29)
= ![\frac{1}{2}(AB)(BC)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28AB%29%28BC%29)
By applying Pythagoras theorem in the given triangle,
AC² = AB² + BC²
(13)² = 5² + BC²
169 = 25 + BC²
BC² = 144
BC = 12
Area of the triangular base = ![\frac{1}{2}(5)(12)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%285%29%2812%29)
= 30 cm²
Height of the triangular prism = 18 cm
Volume of the triangular prism = 30 × 18
= 540 cm³
Volume of one spherical bead = ![\frac{4}{3}\pi r^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E%7B3%7D)
= ![\frac{4}{3}\pi (0.525)^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%280.525%29%5E%7B3%7D)
= 0.606 cm³
Let there are 'n' beads in the triangular prism,
Volume of 'n' beads = Volume of the prism
540 = 0.606n
n = 890.90
n ≈ 890
Therefore, 890 beads can be fitted in the triangular prism.