<span>D. sill
A sill forms when hot magma squeezes between layers of rock to form a hardened sheet of rock. A sill is basically a tabular sheet intrusion between old layers of sedimentary rock, volcanic beds, or in the direction of foliation inherent in metamorphic rock. The word sill means a concordant intrusive sheet.</span>
Answer:
To convert m/sec into km/hr, multiply the number by 18 and then divide it by 5.
Explanation:
please mark as brainliest
Answer:

Explanation:
From the question we are told that:
Crane Length 
Crane Mass 
Arm extension at lifting end 
Arm extension at counter weight end 
Load 
Generally the equation for Torque Balance is mathematically given by



Answer is D. Neutral charge
Answer:
Change in mechanical energy = work done by friction
so it is equal to

Explanation:
As we know that change in mechanical energy must be equal to the work done by non conservative forces only
So here when block moves down the inclined plane then the work done by friction force is given as

here we have

here we know that

so we have


Now the friction force on the block is given as



now work done by the friction is given as

