There are many Autotrophs than consumers because : Autotrophs are the bases of any food chain/web
<h3>Function of Autotrophs </h3>
Autotrophs capture the energy required for every food chain or web from which sustains other organisms in the food chain form sunlight and chemicals. Also there is always more biomass present in the lower levels of the trophic system as biomass decreases as we move up the food chain.
Since autotrophs are producers, for a healthy food chain there would be more autotrophs than consumers.
Hence we can conclude that There are many Autotrophs than consumers because : Autotrophs are the bases of any food chain/web
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I don't know what your options are, but heat moves from the sun moves in 3 ways: radiation, conduction, and convection. I hope this helps at least a little
More work is done when one man lifts the weight using a pulley. Option C is correct.
<h3>What is mechanical advantage ?</h3>
Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtained efficiency of forces in levers and pulley.
It is an effective way of amplify the force in simple machines like lever The theoretical mechanical advantage is defined as the ratio of the force responsible for the useful work in the system to the applied force.
More work is done when one man lifts the weight using a pulley. With the pulley, the mechanical advantage is increasing.
Hence, option C is correct.
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Answer:
The highest electric field is experienced by a 2 C charge acted on by a 6 N electric force. Its magnitude is 3 N.
Explanation:
The formula for electric field is given as:
E = F/q
where,
E = Electric field
F = Electric Force
q = Charge Experiencing Force
Now, we apply this formula to all the cases given in question.
A) <u>A 2C charge acted on by a 4 N electric force</u>
F = 4 N
q = 2 C
Therefore,
E = 4 N/2 C = 2 N/C
B) <u>A 3 C charge acted on by a 5 N electric force</u>
F = 5 N
q = 3 C
Therefore,
E = 5 N/3 C = 1.67 N/C
C) <u>A 4 C charge acted on by a 6 N electric force</u>
F = 6 N
q = 4 C
Therefore,
E = 6 N/4 C = 1.5 N/C
D) <u>A 2 C charge acted on by a 6 N electric force</u>
F = 6 N
q = 2 C
Therefore,
E = 6 N/2 C = 3 N/C
E) <u>A 3 C charge acted on by a 3 N electric force</u>
F = 3 N
q = 3 C
Therefore,
E = 3 N/3 C = 1 N/C
F) <u>A 4 C charge acted on by a 2 N electric force</u>
F = 2 N
q = 4 C
Therefore,
E = 2 N/4 C = 0.5 N/C
The highest field is 3 N, which is found in part D.
<u>A 2 C charge acted on by a 6 N electric force</u>
