1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sukhopar [10]
3 years ago
8

Match each term with the best description. DispersionRayRefractive indexSnell's lawTotal internal reflection Ratio of the speed

of light in a vacuum to the speed of light in a medium Rule for how light is refracted at the boundary between two materials Process that occurs when the angle of incidence is greater than the critical angle Path of a particle of light The separation of light into different frequencies to produce a rainbow
Physics
1 answer:
frozen [14]3 years ago
5 0

Answer:

A) Ratio of the speed of light in a vacuum to the speed of light in a medium (refractive index)

B) Rule for how light is refracted at the boundary between two materials (snell's law)

C) Process that occurs when the angle of incidence is greater than the critical angle (total internal reflection)

D) Path of a particle of light (ray)

E) The separation of light into different frequencies to produce a rainbow (dispersion)

You might be interested in
A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the
Olin [163]

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

m_1v_1+m_2v_2=(m_1+m_2)v   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Next, you replace the values of the rest of the variables:

v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}

hence, just after the collision both cars have a speed of 27m/s

7 0
3 years ago
Why does changing the shape on an object have no affect on the density of that object?
Anna11 [10]
It is because change in the Mass of the object balances the change in the Volume of the object equally...........
8 0
3 years ago
when a temparature of a coin is 75°C, the coin's diameter increases. if the original diameter of a coin is 1.8*10^-2 m and its c
andrey2020 [161]

Answer:

ΔD = 2.29 10⁻⁵ m

Explanation:

This is a problem of thermal expansion, if the temperature changes are not very large we can use the relation

          ΔA = 2α A ΔT

the area is

         A = π r² = π D² / 4

we substitute

         ΔA = 2α π D² ΔT/4

as they do not indicate the initial temperature, we assume that ΔT = 75ºC

    α = 1.7 10⁻⁵ ºC⁻¹

we calculate

          ΔA = 2 1.7 10⁻⁵ pi (1.8 10⁻²) ² 75/4

          ΔA = 6.49 10⁻⁷ m²

by definition

           ΔA = A_f- A₀

           A_f = ΔA + A₀

           A_f = 6.49 10⁻⁷ + π (1.8 10⁻²)² / 4

           A_f = 6.49 10⁻⁷ + 2.544 10⁻⁴

           A_f = 2,551 10⁻⁴ m²

the area is

           A_f = π D_f² / 4

           A_f = \sqrt{4  A_f /\pi }

           D_f = \sqrt{4 \ 2.551 10^{-4} /\pi }

           D_f = 1.80229 10⁻² m

the change in diameter is

           ΔD = D_f - D₀

           ΔD = (1.80229 - 1.8) 10⁻² m

           ΔD = 0.00229 10⁻² m

           ΔD = 2.29 10⁻⁵ m

5 0
3 years ago
Calculate:<br> The time taken for a plane to travel<br> 3,000 km at a speed of 200 m/s
Alborosie

Time = (distance) / (speed)

Distance = 3,000 km  =  3,000,000 meters

Speed = 200 m/s

Time = (3,000,000 m) / (200 m/s)

Time = <em>15,000 seconds</em>

That's 4 hours 10 minutes

6 0
3 years ago
A car takes 10 minutes to travel 10 km calculate average speed of car.​
lisabon 2012 [21]

Answer:

(km/mins) × ( mins/hr) = km/hr

(10/10)×(60/1) =600/10 = 60 km /hr

......

5 0
3 years ago
Other questions:
  • Use image for both problems
    12·1 answer
  • If the work done to stretch an ideal spring by 4.0 cm is 6.0J, what is the spring constant (force constant) of this spring?
    7·2 answers
  • Plz help with all of them! Read instructions. I will give you 30 points. No Joke.
    15·1 answer
  • Cody’s car accelerates from 0M/S 245 in/at Northwoods and 15 seconds what is the acceleration of the car
    12·1 answer
  • Bales of hay of 40 lbf move up a conveyor set at 30° angle to the ground. If the hay bales are moving at 1.5 ft/sec, determine t
    11·1 answer
  • A stuntwoman is going to attempt a jump across a canyon that is 77 m wide. The ramp on the far side of the canyon is 25 m lower
    15·1 answer
  • The axoplasm of an axon has a resistance Rax. The axon's membrane has both a resistance (Rmem) and a capacitance (Cmem). A singl
    14·1 answer
  • Why has the study of genetic differences in intelligence been so controversial?
    15·1 answer
  • Please help me! It’s due soon! Please help!
    10·1 answer
  • A train is traveling at force 15000 N, how much work must it do to travel 10 km?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!