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kotegsom [21]
1 year ago
10

Find the value of X. Round to the nearest tenth HELP ASAP!!!!

Mathematics
1 answer:
never [62]1 year ago
4 0

Answer: 22.5

Step-by-step explanation:

\sin 64^{\circ}=\frac{x}{25}\\\\x=25 \sin 64^{\circ}\\\\x \approx 22.5

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For positive acute angles A and B, it is known that tan A = 35/12 and sin B = 20/29. Find the value of sin(A - B ) in the simple
almond37 [142]

Answer:

\displaystyle \sin(A-B)=\frac{495}{1073}

Step-by-step explanation:

We are given that:

\displaystyle \tan(A)=\frac{35}{12}\text{ and } \sin(B)=\frac{20}{29}

Where both A and B are positive acute angles.

And we want to find he value of sin(A-B).

Using the first ratio, we can conclude that the opposite side is 35 and the adjacent side is 12.

Then by the Pythagorean Theorem, the hypotenuse is:

h = \sqrt{35^2 + 12^2} =37

Using the second ratio, we can likewise conclude that the opposite side is 20 and the hypotenuse is 29.

Then by the Pythagorean Theorem, the adjacent is:

a=\sqrt{29^2-20^2}=21

Therefore, we can conclude that:

So, for A, the adjacent is 12, opposite is 35, and the hypotenuse is 37.

For B, the adjacent is 21, opposite is 20, and the hypotenuse is 29.

We can rewrite sin(A-B) as:

\sin(A-B)=\sin(A)\cos(B)-\cos(A)\sin(B)

Using the above conclusions, this yields: (Note that since A and B are positive acute angles, all resulting ratios will be positive.)

\displaystyle \sin(A-B)=\Big(\frac{35}{37}\Big)\Big(\frac{21}{29}\Big)-\Big(\frac{12}{37}\Big)\Big(\frac{20}{29}\Big)

Evaluate:

\displaystyle \sin(A-B)=\frac{735-240}{1073}=\frac{495}{1073}

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3 years ago
2x^2-12x-32=0 solution
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Step-by-step explanation:

Step 1: Factor left side of equation.

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Step 2: Set factors equal to 0.

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