9514 1404 393
Answer:
see attachments for a table and graph
Step-by-step explanation:
I find it convenient to use a graphing calculator or spreadsheet to do repetitive computations reliably.
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Your specific question asks for h(0):
h(0) = -|0 +2| +1 = -2 +1
h(0) = -1
You may want to check your other table values.
If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:
(x,y)=((6+2)/2, (3+1)/2)=(4,2)
Now we need to find the radius....the diameter is:
d^2=(6-2)^2+(3-1)^2
d^2=16+4
d^2=20 since d=2r, r=d/2, and r^2=d^2/4 so
r^2=5
The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
(h,k)=(4,2) from earlier so:
(x-4)^2+(y-2)^2=5
100 circles and another 100 circles and 76 circles.
Draw in real life it will work.
Another way 2 hundreds 7 tens and 6 ones
A^2 + b^2 = c^2
a^2 + 9^2 = 18^2
a^2 + 81 = 324
a^2 = 243
a = 15.589 = 15.6 feet is the angle the ladder is at :)
Let,
- Number of boys be 3x
- Number of girls be 2x
- Then, Total number of students = 3x + 2x = 5x
It is given that,
➙ Number of girls = 420
Then,
➙ 2x = 420
➙ x = 420/2 = 210
No. of boys = 3x = 630
Then,
➙ Number of students = 5x
➙ Number of students = 5(210)
➙ Number of students = 1050
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