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g100num [7]
1 year ago
5

Most towns use a water tower to store water and provide pressure in the pipes that deliver water to customers. The figure below

shows a spherical water tank that holds 5.80 105 kg of water when full. Note that the tank is vented to the atmosphere at the top and that the pipe delivering water to customer Smith is a height h = 3.75 m above the level of the pipe delivering water to customer Jones. Determine the gauge pressure of the water at the faucet of each house when the tank if full.
There is a spherical water-filled chamber with a vent on top and underneath it is a pipe 18 m long that leads down to the ground. At ground level a horizontal pipe connects the faucet in the Jones house to the water supply. The faucet in the Smith house is connected to the water supply with a pipe at a height h above ground level.
(a) Jones house
Pa

(b) Smith house
Pa
Physics
1 answer:
MatroZZZ [7]1 year ago
8 0

The effective height of the water for Smith's house will be 24.61m.

<h3>How to calculate the height?</h3>

Based on the information given, the volume of the water in sphere will be:

= 4/3πr³ = (5.80 × 10^5)/1000

= 4.18r³ = 580

r³ = 138.7

r = 5.18m

The effective height of the water will be:

= 18.0 + 2(5.18)

= 28.36

The gauge pressure at Faucet of Jones house will be:

= pgh

= 1000(9.8)(28.36)

= 277.9kPa

The effective height of the water for Smith's house will be:

= 18.0 + 2(5.18) - 3.75

= 24.61m

The gauge pressure at Faucet of Jones house will be:

= 1000 × 9.8 × 24.61

= 241.2kPa

Learn more about height on:

brainly.com/question/983412

#SPJ1

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Answer:

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Explanation:

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According to record time,

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Hence, The best estimate of the depth of the well is 2.3 sec.

6 0
3 years ago
n a level football field a football is projected from ground level. It has speed 9.0 m/sm/s when it is at its maximum height. It
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T = 0.225 s

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If the coefficient of kinetic friction between tires and dry pavement is 0.84, what is the shortest distance in which you can st
liberstina [14]

Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the  the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

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4 0
3 years ago
A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at
baherus [9]

Hello!

Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

\Sigma \tau = 0

We have two torques acting on the rod:
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- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)

Both of these act in opposite directions. Let's use the equation for torque:
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Doing the summation using their respective lever arms:

0 = L Tsin\theta  - dF_g

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Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

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