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alina1380 [7]
1 year ago
14

When the distance increases, the electrostatic force____; we call this relationship proportional

Physics
2 answers:
Ipatiy [6.2K]1 year ago
8 0

Answer:

See below

Explanation:

When the distance increases, the electrostatic force <u> DECREASES</u>; we call this relationship <u> INVERSELY</u>  proportional

Alik [6]1 year ago
5 0

Answer:

I think decreases inversely

Explanation:

the third

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4- by eating food only will you get energy?​
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yes

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The<br> is the time it takes for a wave to complete one cycle.
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2 years ago
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Why does the area around the equator stay about the same temperature year round?
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3 years ago
The rectangular plates in a parallel-plate capacitor are 0.063 m x 5.4 m. A distance of 3.5 x 10^-5m separate the plates. The pl
Aleks04 [339]

The capacitance of the capacitor is 1.8\cdot 10^{-9}F

Explanation:

The capacitance of a parallel-plate capacitor is given by the equation

C=\frac{k\epsilon_0 A}{d}

where

k is the dielectric constant of the medium

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the capacitor in this problem, we have:

k = 2.1 is the dielectric constant

d=3.5\cdot 10^{-5}m is the separation between the plates

A=0.063m \cdot 0.054m = 0.0034 m^2 (I assumed that 5.4 m is a typo, since it is not a realistic size for the side of the plate)

Therefore, the capacitance of the  capacitor is

C=\frac{(2.1)(8.85\cdot 10^{-12})(0.0034)}{3.5\cdot 10^{-5}}=1.8\cdot 10^{-9}F

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

5 0
3 years ago
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