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arlik [135]
3 years ago
10

If you have a book "sitting" on a table, the two forces acting on the book will be its

Physics
2 answers:
9966 [12]3 years ago
5 0
Yes there would be forces acting in the book
pishuonlain [190]3 years ago
3 0

Answer:Yes, there are forces acting on the book.

If the book is kept on a flat table then the forces acting on the book are Balanced in nature.

The weight of the book(=mg) acting downwards and the Normal Reaction acting upwards. The balanced nature of these 2 forces causes book to stay still on the table!

Explanation:

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Rashid [163]
D.quadruple is the answer
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While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the
BartSMP [9]

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

d = v_i * t + \frac{1}{2} at^2

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3 0
3 years ago
A baseball of mass m = 0.31 kg is spun vertically on a massless string of length L = 0.51m. The string can only support a tensio
natulia [17]

Given data:

* The mass of the baseball is 0.31 kg.

* The length of the string is 0.51 m.

* The maximum tension in the string is 7.5 N.

Solution:

The centripetal force acting on the ball at the top of the loop is,

\begin{gathered} T+mg=\frac{mv^2}{L}_{} \\ v^2=\frac{L(T+mg)}{m} \\ v=\sqrt[]{\frac{L(T+mg)}{m}} \end{gathered}

For the maximum velocity of the ball at the top of the vertical circular motion,

v_{\max }=\sqrt[]{\frac{L(T_{\max }+mg)}{m}}

where g is the acceleration due to gravity,

Substituting the known values,

\begin{gathered} v_{\max }=\sqrt[]{\frac{0.51(7.5_{}+0.31\times9.8)}{0.31}} \\ v_{\max }=\sqrt[]{\frac{0.51(10.538)}{0.31}} \\ v_{\max }=\sqrt[]{17.34} \\ v_{\max }=4.16\text{ m/s} \end{gathered}

Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.

8 0
1 year ago
What is formula for time and velocity
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4 0
3 years ago
an airplane travels 2100 km at a speed of 1000 km/h for the next 1300 km. whatis the average speed for this plane trip?
Vanyuwa [196]

wouldn't it be 1000 km/h considering the plane was travelling the same speed for over half the trip?

4 0
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