Answer:
(a) 
(b) 
Explanation:
(a) In the given problem, the turning fork has a frequency of
. Then, a woman runs toward the wall with a speed of
. From the principle of light reflection, the reflection of the sound from the fork reach the woman at a speed of v. Thus, the beat frequency is:

(b) In this part, the woman moves away from the water which is in contrast to part (a). Thus the beat frequency is:

Answer:
When a sound source moves faster than the speed of sound, a shock wave is produced as the sound waves interfere. A sonic boom is the intense sound that occurs as the shock wave moves along the ground.
More importantly, all of the energy gets concentrated into a very small distance this is called a shock wave. In this case, the observer does not hear the approaching source at all until the shock wave hits with all of the energy in the wave. For sound waves, this can cause a very loud noise, called a sonic boom.
Sonic booms produced by aircraft flying supersonic at altitudes of less than 100 feet, creating between 20 and 144 pounds overpressure, have been experienced by humans without injury. Damage to eardrums can be expected when overpres- sures reach 720 pounds
Explanation:
marke as brainliest
Helium... from the greek word helios... the sun
<span>selenium... from the greek word selene... the moon </span>
<span>palladium.. after the asteroid pallas </span>
<span>tellurium...from the greek word tellus... the earth </span>
<span>mercury...after the planet mercury </span>
<span>cerium... after the asteroid ceres </span>
<span>uranium...after the planet uranus </span>
<span>neptunium.. after the planet neptune </span>
<span>plutonium.. after the planet pluto</span>
Answer:
The resonant frequency of this circuit is 14.5 kHz.
Explanation:
Given that,
Inductance of a parallel LCR circuit, 
Capacitance of parallel LCR circuit, 
At resonance the inductive reactance becomes equal to the capacitive reactance. The resonant frequency is given by :



or
f = 14.5 kHz
So, the resonant frequency of this circuit is 14.5 kHz. Hence, this is the required solution.