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Alexxx [7]
4 years ago
8

Which of the following choices describes the type of image formed by a plane mirror?

Physics
2 answers:
Aleks04 [339]4 years ago
8 0
Virtual upright and the same size
gizmo_the_mogwai [7]4 years ago
3 0

Answer:

Virtual, Upright and the same size

Explanation:

As we know for plane mirror we have

d_i = -d_0

image distance is same as that of object distance but on opposite side of the mirror.

now for the magnification we have

m = -\frac{d_i}{d_0}

m = +1

since magnification is positive so it must be virtual and upright image and since the magnitude of magnification is exactly 1 so it must be of same size as that of object size

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The energy processed and used by living beings is <br>​
Molodets [167]

Answer:

Nutrition , heat , wind

Explanation:

6 0
3 years ago
Which device increases or decreases voltage as electricity is transmitted from power plants to homes and businesses?
Leona [35]

Answer:Transformer

Explanation:All the other devices generate their own electricity apart from power line and Transformer, power line just carries electricity. A transformer can be used to step up or step down voltages from a source.

4 0
3 years ago
Read 2 more answers
A 30-cm-diameter, 1.2 kg solid turntable rotates on a 1.2-cm-diameter, 450 g shaft at a constant 33 rpm. When you hit the stop s
skelet666 [1.2K]

Answer:

frictional force = 0.52 N

Explanation:

diameter of turn table (D1) = 30 cm = 0.3 m

mass of turn table (M1) = 1.2 kg

diameter of shaft (D2) = 1.2 cm = 0.012 m

mass of shaft (M2) = 450 g = 0.45 kg

time (t) = 15 seconds

acceleration due to gravity (g) = 9.8 m/s^{2}

radius of turn table (R1) = 0.3 / 2 = 0.15 m

radius of shaft (R2) = 0.012 / 2 = 0.006 m

total moment of inertia (I) = moment of inertia of turn table + moment of inertia of shaft

I = 0.5(M1)(R1)^{2} + O.5 (M2)(R2)^{2}

I =  0.5(1.2)(0.15)^{2} + O.5 (0.45)(0.006)^{2}

I = 0.0135 + 0.0000081 = 0.0135081

ω₁ = 33 rpm = 33 x \frac{2π}{60} = 3.5 rad/s

α = -ω₁/t = -3.5 / 15 = -0.23 rad/s^{2}

torque = I x α

torque = 0.0135081 x (-0.23) = - 0.00311 N.m

torque = frictional force x R2

- 0.00311 = frictional force x 0.006

frictional force = 0.52 N

6 0
4 years ago
An earthquake’s epicenter is _____.
Evgen [1.6K]
The point in which it originates.
4 0
3 years ago
Read 2 more answers
A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.8 m/s rel
Svetach [21]

I'm assuming the question is what is the robin's speed relative to to the ground...

Create an equation that describes its relative motion.

rVg = rVa + aVg


Substitute values.

rVg = 12 m/s [N] + 6.8 m/s [E]


Use vector addition.

| rVg | = √ | rVa |² + | aVg |²

| rVg | = √ 144 m²/s² + 46.24 m²/s²

| rVg | = √ 19<u>0</u>.24 m²/s²

| rVg | = 1<u>3</u>.78 m/s


Find direction.

tanФ = aVg / rVa

tanФ = 6.8 m/s / 12 m/s

Ф = 29°


Therefore, the velocity of the robin relative to the ground is 14 m/s [N29°E]

4 0
3 years ago
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