Answer:
<h2>The length of the line segment VT is 13 units.</h2>
Step-by-step explanation:
We know that SU and VT are chords. If the intersect at point R, we can define the following proportion

Where

Replacing all these expressions, we have

Solving for
, we have

Now, notice that chord VT is form by the sum of RT and RV, so

Replacing the value of the variable

Therefore, the length of the line segment VT is 13 units.
A and D, sorry if I’m wrong.
We are given
Vertical asymptotes:
Firstly, we will factor numerator and denominator
we get

We can see that (x-3) is common in both numerator and denominator
so, we will only set x+3 to 0
and then we can find vertical asymptote


Hole:
We can see that (x-3) is common in both numerator and denominator
so, hole will be at x-3=0

Horizontal asymptote:
We can see that degree of numerator is 2
degree of denominator is also 2
for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator
and we get
y=1
now, we can draw graph
Graph:
Answer: 4y/(y+3)
Explanation:
{(2y)(4y-12)}/{(y-3)(2y+6)}
= (8y^2 - 24y)/(2y^2 + 6y - 6y - 18)
= (8y^2 - 24y)/(2y^2 - 18)
= {8y(y-3)}/{2(y+3)(y-3)}
= 2 * 4y/{2(y+3)}
= 4y/(y+3)
2 weeks = 14 day
14 * 15 = 210 seconds
210/60=3 hours and 30 minutes or 3.5 hours.