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Mademuasel [1]
3 years ago
5

The milky way galaxy is most likely an example of which type of galaxy?

Physics
2 answers:
timofeeve [1]3 years ago
7 0
The Milky way galaxy belongs to so called Barred Spiral galaxies.
Art [367]3 years ago
4 0

Hey, how u doin'? Here's your answer.

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a stone attached to 1m long string is moving with the speed of 5ms in a circle find the centripetal acceleration of the stone​
Dafna1 [17]

Answer:

The centripetal acceleration of the stone is 5 m/s²

Explanation:

The length of the string to which the stone is attached, r = 1 m

The speed with which the string is rotated, v = 5 m/s

The centripetal acceleration, a_c, is given as follows;

a_c = \dfrac{v^2}{r}

Therefore, the centripetal acceleration of the stone found as follows;

a_c = \dfrac{(5 \ m/s)^2}{1 \ m} = 5 \ m/s^2

The centripetal acceleration of the stone, a_c = 5 m/s².

5 0
3 years ago
Explain why is it easy to slip on a floor that is wet
zmey [24]
The water creates less friction between your foot and the ground
6 0
3 years ago
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Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. The electric field at a po
gregori [183]

Answer:

E = 0    r <R₁

Explanation:

If we use Gauss's law

      Ф = ∫ E. dA = q_{int} / ε₀

in this case the charge is distributed throughout the spherical shell and as we are asked for the field for a radius smaller than the radius of the spherical shell, therefore, THERE ARE NO CHARGES INSIDE this surface.

Consequently by Gauss's law the electric field is ZERO

           E = 0    r <R₁

6 0
3 years ago
Leia is presenting her project about gravity to her class. She says that both mass and distance affect how strong the gravitatio
DaniilM [7]

Answer:

No, because as distance increases, gravitional force decreases.

5 0
3 years ago
An 80.0 kg skier slides down a hill shaped as shown. Assume
umka21 [38]

The height above the ground from where the skier start is 11.5 m.

<h3>Conservation of energy</h3>

The height above the ground from where the skier start is determined by applying the principle of conservation of energy as shown below;

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

h = \frac{v^2}{2g} \\\\h = \frac{15^2}{2 \times 9.8} \\\\h = 11.5 \ m

Thus, the height above the ground from where the skier start is 11.5 m.

Learn more about conservation of energy here: brainly.com/question/166559

8 0
2 years ago
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