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2 years ago

What is the symbol for a change in position? Ad p d Ap

Physics

1 answer:

Rudiy272 years ago

7 0

change in position of an object we use the

symbol ∆×\ delta×∆×for displacement, where ∆. means

"change" ∆ vector quantity with units of distances start

text ,d,I,s,t,a,n,c,e , end text.

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A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp

NISA [10]

A) 750 m

First of all, let's find the wavelength of the microwave. We have

$f=12GHz=12\cdot 10^9 Hz$ is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

So the wavelength of the beam is

$\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m$

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

$y=\frac{m\lambda D}{a}$

where

m = 1 since we are interested only in the central fringe

D = 30 km = 30,000 m

a = 2.0 m is the aperture of the antenna (which corresponds to the width of the slit)

Substituting, we find

$y=\frac{(1)(0.025 m)(30000 m)}{2.0 m}=375 m$

and so, the diameter is

$d=2y = 750 m$

B) 0.23 W/m^2

First we calculate the area of the surface of the microwave at a distance of 30 km. Since the diameter of the circle is 750 m, the radius is

$r=\frac{750 m}{2}=375 m$

So the area is

$A=\pi r^2 = \pi (375 m)^2=4.42\cdot 10^5 m^2$

And since the power is

$P=100 kW = 1\cdot 10^5 W$

The average intensity is

$I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2$

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2 years ago

What impact can a very large volcanic eruption have on earths climate

Vaselesa [24]

Answer:

It could instantly kill all life on Earth
It could block out the sun and kill off all plants
It could block out the sun and freeze everything
It could throw sulfur millions of miles and kill everything that 'inhales' it

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3 years ago

What is the speed of sound in air that has a temperature of 19.9 celcius

klasskru [66]

Answer4.4 :

Explanation:

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3 years ago

what happens to the volume when temperature is held constant and the pressure is increased to 125 kPa

Semenov [28]

The volume decreases, by a factor of

(the original pressure/(125 kPa).

5 0

3 years ago

The rope of a swing is 3.10 m long. Calculate the angle from the vertical at which a 76.0 kg man must begin to swing in order to

kakasveta [241]

Answer:

The angle from the vertical is 48.72°

Explanation:

Given :

Length of rope $l = 3.10$ m

Mass of man $m = 76$ Kg

Mass of car $M = 1520$ Kg

Velocity of car $v = 1.01$ $\frac{m}{s}$

According to conservation law,

Potential energy of man is converted to kinetic energy of car moving,

$\frac{1}{2} M v^{2} = mgh$

We calculate height,

$h = \frac{M v^{2} }{2mg}$

$h = \frac{1520(1.01)^{2} }{2\times 75 \times 9.8}$ ( ∵ $g = 9.8 \frac{m}{s^{2} }$ )

$h = 1.05$ m

This is the distance of the rope at the bottom,

So we take difference of it.

⇒ $3.10 - 1.05 = 2.05$

We can calculate angle between them,

$\cos \theta = \frac{2.05}{3.10} = 0.6597$

$\theta =$ 48.72°

Therefore, the angle from the vertical is 48.72°

8 0

3 years ago