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Komok [63]
3 years ago
7

Do you think antiseptic creams and lotions play an important part in our dayto day life? ​

Physics
2 answers:
timama [110]3 years ago
8 0

Answer:

no, otherwise they just cause a side effect on our lives

Komok [63]3 years ago
6 0
Yes, it keeps your skin from getting burnt when you play out side so much.
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What does the negative sign in F = –kx mean?
Andru [333]
The force is opposite to the displacement
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3 years ago
Projectile Motion—A tennis ball is thrown out a window 28 m above the ground at an initial velocity of 15.0 m/s and 20.0° below
NNADVOKAT [17]

Answer:

The distance will be x = 41.7 [m]

Explanation:

We must first find the components in the x & y axes of the initial velocity.

(v_{o})_{x} = 15*cos(20)= 14.09[m/s]\\(v_{o})_{y} = 15*sin(20)= 5.13[m/s]

The acceleration is the gravity acceleration therefore.

g = 9.81 [m/s^2]

Now we can calculate how long it takes to fall.

y=(v_{o})_{y}*t-0.5*g*t^2\\-28 = 5.13*t-0.5*9.81*t^2\\-28=-4.905*t^2+5.13*t\\4.905*t^2-5.13*t=28\\t = 2.96[s]

With this time we can find the horizontal distance that runs the projectile.

x=(v_{o})_{x}*t\\x=14.09*2.96\\x=41.7[m]

5 0
3 years ago
A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a d
Angelina_Jolie [31]

A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a distance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?

If the distance from the source is doubled. The amplitude of the magnetic field is smaller 4 times.

4 0
3 years ago
An automobile of mass 1.46 cross times to the power of blank 10 cubed kg rounds a curve of radius 25.0 m with a velocity of 15.0
Vsevolod [243]

The centripetal force exerted on the automobile while rounding the curve is 1.31\times10^4 N

<u>Explanation:</u>

given that

Mass\ of\ the\ automobile\ m  =1.46\times 10^3 kg\\radius\ of\ the\ curve\ r =25 m\\velocity\ of\ the\ automobile\ v=15m/s\\

Objects moving around a circular track will experience centripetal force towards the center of the circular track.

centripetal\ force=mv^2/r\\=1.46\times10^3\times15^2/25\\=1.46\times 10^3\times 225/15\\=1.31\times 10^4 N

4 0
3 years ago
Using the information given in the problem introduction and assuming that the third driver is telling the truth, determine wheth
Thepotemich [5.8K]

Answer:

The speed of driver N is 22.1594 m/s

Explanation:

the solution is in the attached Word file

Download docx
8 0
3 years ago
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