What is the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis according to the balanced equation:
1 answer:
Taking into account the reaction stoichiometry, the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis is 25.956 grams.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
2 H₂O → 2 H₂ + O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- H₂O: 2 moles
- H₂: 2 moles
- O₂: 1 mole
The molar mass of the compounds is:
- H₂O: 18 g/mole
- H₂: 2 g/mole
- O₂: 32 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- H₂O: 2 moles ×18 g/mole= 36 grams
- H₂: 2 moles ×2 g/mole= 4 grams
- O₂: 1 mole ×32 g/mole= 32 grams
The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
<h3>Theorical yield of O₂</h3>The following rule of three can be applied: if by reaction stoichiometry 36 grams of water form 32 grams of oxygen, 29.2 grams of water form how much mass of oxygen?
<u><em>mass of oxygen= 25.956 grams</em></u>
Finally, the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis is 25.956 grams.
Learn more about the reaction stoichiometry:
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Answer : The enthalpy of the reaction is, -2552 kJ/mole
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given enthalpy of reaction is,
The intermediate balanced chemical reactions are:
(1)
(2)
(3)
(4)
Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :
(when we are reversing the reaction then the sign of the enthalpy change will be change.)
The expression for enthalpy of the reaction will be,
Therefore, the enthalpy of the reaction is, -2552 kJ/mole